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3 years ago

Write an equation of the line that is perpendicular to the line y = 2x + 8, and which passes through the point (6,-2).

Mathematics

1 answer:

klemol [59]3 years ago

3 0

Answer:A

Step-by-step explanation:

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In the rectangular trapezoid ABCD AC is driven by a CD (see figure).

eimsori [14]

Answer:

solution given:

let's see only in a right-angled triangle Δ ACD.

AC=3 units

AD=5 units

since Δ ACD is a right-angled triangle. It satisfies Pythagoras law

$AD^{2}=AC^{2}+CD^{2}$

25=9+ $CD^2$

$CD^2$ =25-9=16

$CD=\sqrt{16} =4 units$

Now

Area of rectangle Δ ACD= $\frac{1}{2} CD*AC=\frac{1}{2}*4*3=6\: square \:units$

similarly,

$\frac{1}{2} AD*CE=6\: square \:units\\ 5*CE=6*2\\CE=\frac{12}{5}=2.4 units$

since AB=CE=2.4 units

Δ ACE is a right-angled triangle. It satisfies Pythagoras law.

$AC^{2}=AE^{2}+CE^{2}\\3^2=AE^2+2.4^2\\9-5.76=AE^2\\AE and BC=\sqrt{1.24} =1.11 units$

now

area of trapezoid=area ofΔACD+Area of ΔABC

=6+ $\frac{1}{2}AB*BC=6+\frac{1}{2}*2.4*1.11=6+1.33 =7.33\: square \:units$

6 0

2 years ago

Macy has completed 78% of the 50 questions on the test.how many questions has Macy completed

m_a_m_a [10]

$p\%=\frac{p}{100}\\\\78\%=\frac{78}{100}=0.78\\\\78\%\ of\ the\ 50\ i\ equal\ 0.78\times50=\boxed{39}$

3 0

3 years ago

Please help. what is the quotient of 4m^12/x-1÷x^2/8m^3 assume x ≠ 0 and m≠0

Sergio039 [100]

Answer:

$\frac{32m^{15}}{x^3-x^2}$

Step-by-step explanation:

The given expression is: $\frac{4m^{12}}{x-1}\div \frac{x^2}{8m^3}$

We multiply by the reciprocal of the second fraction:

$\frac{4m^{12}}{x-1}\times \frac{8m^3}{x^2}$

We cancel out the common factors to get;

$\frac{32m^{12+3}}{x^2(x-1)}$ , where $x\ne0$ and $m\ne0$

We simplify to get:

$\frac{32m^{15}}{x^3-x^2}$

5 0

3 years ago

I don’t know how to do this and I need know know how quick!!

4vir4ik [10]

It is the Top left answer!

3 0

3 years ago

Use the function below to find

il63 [147K]

Answer:

f(x) =1/3 × 4^x

f(4) = 1/3 × 4⁴

= 1/3 × 256

= 256/3

Hope this helps

8 0

3 years ago