If you are 16 years old then you are a teenager Question 14
Answer:
x+1 , x<-1
x²-bx-4 , -1≤x≤4
1/2 x +a
substitute x=-1 , continuous everywhere
x+1=x²-bx-4 when x=-1
-1+1=-1²-b-4
<h2>1+b-4=0 ⇒ +b-3 ⇒ b=3</h2>
then for :
x²-bx-4=1/2 x +a for x=4
4²-4b-4=1/2x+a
16-4(3)-4=4/2+a
16-12-4-2=a
<h2>a=-2</h2>
the equations will be :
x+1
x²-3x-4
1/2x-2
I hope this help
A is correct :)
Hope this helps!
Answer:
27
Step-by-step explanation:
Out of those numbers and assuming the equation is f(x) = 6x^2=3
f(-2)= 6(-2)^2+3
