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Ivenika [448]
4 years ago
8

Use the distributive property to expand: x^-3 y^0(x^2-3x^5 y^4)

Mathematics
1 answer:
Soloha48 [4]4 years ago
4 0

{x}^{ - 3}  {y}^{0} ( {x}^{2}  - 3 {x}^{5}  {y}^{4} ) \\  =  {x}^{ - 3}  (1) ( {x}^{2}  - 3 {x}^{5}  {y}^{4} ) \\  =  {x}^{ - 1}  - 3 {x}^{2}  {y}^{4}

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Find the missing side of this right
I am Lyosha [343]

Answer:

Step-by-step explanation:

square of 15 + square of x = square of 21

225 + square of x = 441

441 - 225 = 216

x = 216

6 0
3 years ago
ſ x - 5y = -9( 4x + 4y = - 12Step 1 of 2: Determine if the point (-4,1) lies on both of the lines in the system of equations by
Phoenix [80]

Given:

\begin{gathered} x-5y=-9\ldots\ldots(1) \\ 4x+4y=-12\ldots\text{.}\mathrm{}(2) \end{gathered}

The given point is (-4,1)

Let's check the ordered pair (-4,1) in the first equation

\begin{gathered} x-5y=-9 \\ (-4)-5(1)=-9 \\ -4-5=-9 \\ -9=-9 \end{gathered}

Hence, (-4,1) is a solution of the first equation x-5y=-9.

Now, let's check (-4,1) in the second equation.

\begin{gathered} 4x+4y=-12 \\ 4(-4)+4(1)=-12 \\ -16+4=-12 \\ -12=-12 \end{gathered}

So, (-4,1) is a solution of the second equation 4x+4y=-12.

Hence, (-4,1) is a solution of both equation in the system, then it is a solution to the overall system.

3 0
1 year ago
Every person has blood type O, A, B, or AB. A random group of people are blood-typed, and the results are shown in the table.
Evgesh-ka [11]

Answer:

12%

Step-by-step explanation:

P=\frac{6}{22+20+6+2} =.12

6 0
3 years ago
The perimeter of a rectangle is 141 feet, and the length is twice the width. What are the dimensions of the rectangle?
JulijaS [17]
Widths = 23.5feet
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3 0
4 years ago
If
likoan [24]

It's easy to show that 7\tan(4x) is strictly increasing on x\in\left[0,\frac\pi8\right]. This means

M = \max \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/12} = 7\sqrt3

and

m = \min \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/16} = 7

Then the integral is bounded by

\displaystyle 7\left(\frac\pi{12} - \frac\pi{16}\right) \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le 7\sqrt3 \left(\frac\pi{12} - \frac\pi{16}\right)

\implies \displaystyle \boxed{\frac{7\pi}{48}} \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le \boxed{\frac{7\sqrt3\,\pi}{48}}

7 0
2 years ago
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