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dedylja [7]
3 years ago
13

A biometric security device using fingerprints erroneously refuse to admit 1 in 1,000 authorized person from a facility containi

ng classified information. The device will erroneously admit 1 in 1,000,000 unauthorized persons. Assume that 95 percent of those who seek access are authorized. If the alarm goes off and a person is refused admission, what is the probability that the person was really authorized?
Mathematics
1 answer:
solong [7]3 years ago
7 0

Answer:

0.01864

Step-by-step explanation:

Let A be the event that a person was authorized and NA be the event that the person was not authorized. Let R be the event that a person was refused admission and G be the event that a person was granted admission.

Then we have to find P(A|R) = [P(A)*P(R|A)]/P(R)

putting value we get

P(R) = P(A)P(R|A) + P(NA)P(R|NA) = 0.95*(1/1000) + 0.05*((1,000,000-1)/1,000,000) = 0.0.05094995

P(A|R) = [P(A)*P(R|A)]/P(R)

= [0.95*(1/1000)]/(0.05094995)

=0.01864

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5 0
3 years ago
A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12.3 years, and standard deviation of
Zolol [24]

Answer:

probability of lasting longer = 1.7%

Step-by-step explanation:

We are given:

x' = 14 years

μ = 12.3 years

s = 0.8 years

Thus, let's use the formula for the Z-score value which is;

z = (x' - μ)/s

Thus;

z = (14 - 12.3)/0.8

z = 2.125

From the z-distribution table attached, the p-value is ;

P(x' > 2.125) = 1 - 0.983 = 0.017 = 1.7%

Thus,probability of lasting longer = 1.7%

5 0
3 years ago
Mei Mei invested $1700 in an account that pays 3% interest compounded annually.
algol [13]

Answer:

$2728

Step-by-step explanation:

Use compound interest formula:

A = P(1 + \frac{r}{n})^{nt}

P = 1700, r = 0.03, n = 1, t = 16

Plug in numbers:

A = 1700(1 + \frac{0.03}{1})^{(1)(16)}

Simplify:

A = 1700(1.3)^{16

Use calculator:

A = 2728

4 0
2 years ago
Can someone get the answer and explain i will give brainliest.
uranmaximum [27]
Answer: (a^2bc)^2 for the first one

6 0
3 years ago
A parking lot has seventy-six parking spaces numbered from 1 to 76. There are no cars in the parking lot when Jillian pulls in a
Elodia [21]

Answer:

40/76 or 10/19 or 52.63% (they are all equivalent)

Step-by-step explanation:

there are 76 parking spaces in total

30 parking spaces have numbers that are less than 31 (1 - 30)

that means that there are 76 - 30 = 46 spaces that are numbered 31 or higher

so the probability that Jillian parks on a parking space with a number ≥ 31 is 40/76 or 10/19 or 52.63%

8 0
2 years ago
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