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vagabundo [1.1K]
2 years ago
11

How do you solve f-3/4=5/6?

Mathematics
1 answer:
gulaghasi [49]2 years ago
6 0

Answer:

f =38

Step-by-step explanation:

f-3/4=5/6

f-3×6=5×4

f-18 =20

f =20+18

f =38

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A fruit seller packed some apples into 15 small cartons and 20 big cartons. Each big carton contained 15 more apples than each s
ehidna [41]

Answer:

720 apples

Step-by-step explanation:

Let A be the number of apples in the small pack.

QTY for Small Cartons is 15A,

QTY for Big Cartons is 20(A+15) = 20A+300

From small cartons makes 25% or 1/4 of total, means the big carton makes 75% of total, or 3/4 of total. This also means the qty in big carton is 3 times of small carton

20A+300 = 3X (15A)= 45A

300 = 25A

A=12

Altogether = 15A+(20A+300) = 720 Apples

7 0
2 years ago
Find the volume of a right rectangular prism with a length of 3, a width of 5, and a height of 6.
Yuki888 [10]
V = L * W * H
V = 3 * 5 * 6
V = 90 cubic units
3 0
3 years ago
875 rounded to nearest ten
velikii [3]
880
Underline the number in the tens place
look to the right
if number is greater than 5
add 1 to the underlined number
leave the numbers behind the underlined number zero
4 0
3 years ago
Read 2 more answers
Jocelyn is training for a race by running several miles each day. she tracks her progress by recording her average speed in minu
Luden [163]

Finding the regression equation, her average speed on the 9th day should be expected to be of 6.92 minutes per mile.

<h3>How to find the equation of linear regression using a calculator?</h3>

To find the equation, we need to insert the points (x,y) in the calculator.

Researching the problem on the internet, the values of x and y are given as follows:

  • Values of x: 1, 2, 3, 4, 5, 6.
  • Values of y: 8.2, 8.1, 7.5, 7.8, 7.4, 7.5.

Hence, using a calculator, the equation for the average minutes per mile after t days is given by:

V(t) = -0.15143t + 8.28

Hence, for the 9th day, t = 9, hence the estimate is:

V(9) = -0.15143(9) + 8.28 = 6.92 minutes per mile.

More can be learned about regression equations at brainly.com/question/25987747

#SPJ1

4 0
2 years ago
A random sample of 180 microbiology students were asked how many science classes he or she was enrolled in August 1990. The resu
frutty [35]

Answer:

z=\frac{1.83-1.94}{\sqrt{\frac{1.48^2}{180}+\frac{1.62^2}{180}}}}=-0.673  

p_v =2*P(z

Comparing the p value with the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the two means

Step-by-step explanation:

Data given and notation

\bar X_{1}=1.83 represent the mean in 1990

\bar X_{2}=1.94 represent the mean for 2005

s_{1}=1.48 represent the sample deviation for 1990

s_{2}=1.62 represent the sample standard deviation for 2005

n_{1}=180 sample size for 1990

n_{2}=180 sample size for 2005

t would represent the statistic (variable of interest)

\alpha=0.05 significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different, the system of hypothesis would be:

Null hypothesis:\mu_{1}=\mu_{2}

Alternative hypothesis:\mu_{1} \neq \mu_{2}

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

z=\frac{1.83-1.94}{\sqrt{\frac{1.48^2}{180}+\frac{1.62^2}{180}}}}=-0.673  

What is the p-value for this hypothesis test?

Since is a bilateral test the p value would be:

p_v =2*P(z

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the two means

8 0
4 years ago
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