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3 years ago

8a²b-16ab+24a = 8a(ab-2b+3)

Mathematics

1 answer:

NARA [144]3 years ago

6 0

8a^2b +16ab+24a=8a^2b +16ab+24a

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What is true about multiples of 6?

Ivan

Answer:

Each multiple will always be divisible by 3

Step-by-step explanation:

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3 years ago

I NEED HELP PLEASE !!!! :(

Triss [41]

Answer:

Step-by-step explanation:

(2)/((6)√(8))*√(2)-((18)/√81))-2)

(6)sqrt√8 = 6sqrt √2³= 2^3/6=2^1/2= √2

(2√2)/√2 -(-18/√9²)-2)

2-(-18/9 -2)

2-(-2-2)=2+4=6

4 0

3 years ago

Solve the system of equations by substitution. 3/8 x + 1/3 y =17/24 and <br> x + 7y = 8

goblinko [34]

$\left \{ {{ \frac{3}{8}x+ \frac{1}{3}y = \frac{17}{14} } \atop {x+7y=8}} \right.$

To solve this system by substitution, first isolate x in the second equation.

$x+7y=8$
$x+7y-7y=8-7y$
$x=8-7y$

Now, plug this expression ( $8-7y$ ) for x in the top equation to solve for y.

$\frac{3}{8} (8-7y)+ \frac{1}{3} y= \frac{17}{14}$
$3- \frac{21}{8} y+ \frac{1}{3} y= \frac{17}{24}$
$72-63y+8y=17$
$72-55y=17$
$-55y=17-72$
$-55y=-55$
$y=1$

Now that you have y, plug it into the second equation and solve for x.

$x+7y=8$
$x+7(1)=8$
$x+7=8$
$x=1$

Last step is to plug your x- and y-values in to both equations to check your work.

$\frac{3}{8} (1)+ \frac{1}{3} y= \frac{17}{24}$

$\frac{3}{8} * \frac{3}{3} = \frac{9}{24} ; \frac{1}{3} * \frac{8}{8} = \frac{8}{24}$

$\frac{9}{24} + \frac{8}{24} = \frac{17}{24}$ <--True

$1+7(1)=8$
$1+7=8$ <--True

Answer:
$x=1 \\ y=1$

5 0

4 years ago

Solve for k.<br>7k - 2 ≥ -9

Akimi4 [234]

Answer: k ≥ -1

Step-by-step explanation:

7k - 2 ≥ -9

add two to both sides

7k ≥ -7

k ≥ -1

6 0

4 years ago

Read 2 more answers

Can u pls help me with this question

Svet_ta [14]

Answer:

I think is 2/9 but I may be wrong

8 0

3 years ago

8a²b-16ab+24a = 8a(ab-2b+3)​

8a²b-16ab+24a = 8a(ab-2b+3)