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Neporo4naja [7]
3 years ago
9

8a²b-16ab+24a = 8a(ab-2b+3)​

Mathematics
1 answer:
NARA [144]3 years ago
6 0
8a^2b +16ab+24a=8a^2b +16ab+24a
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Then one side of it will be 'x',and the other side will be the value of 'x'.
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The base of a parallelogram is (2x + 3) units and the corresponding height is (3x – 2) units. Find the area of the parallelogram
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Step-by-step explanation:

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Question Help
klasskru [66]

Answer:

16 times

Step-by-step explanation:

\textsf{Volume of a cone}=\sf \dfrac{1}{3} \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}

If only the radius is changed, the change in volume will be proportionate to the multiplicative factor squared.

\sf \implies Volume =\dfrac{1}{3} \pi (ar)^2h=\dfrac{1}{3} \pi (a^2)r^2h

Therefore, if the cone is quadrupled (multiplied by 4), the volume of the larger cone will be 4² times greater than the volume of the smaller cone, so <u>16 times greater </u>than the smaller cone.

<h3><u>Proof</u></h3>

Given:

  • radius = 6
  • height = 9

Substituting the given values into the formula:

\sf \implies Volume =\dfrac{1}{3} \pi (6)^2(9)=108 \pi \: \:cubic\:units

If the radius is quadrupled:

  • radius = 6 × 4 = 24
  • height = 9

Substituting the new given values into the formula:

\sf \implies Volume =\dfrac{1}{3} \pi (24)^2(9)=1728 \pi \: \:cubic\:units

To find the number of times greater the volume of the large cone is than the volume of the smaller cone, divide their volumes:

\sf \implies \dfrac{V_{large}}{V_{small}}=\dfrac{1728\pi}{108\pi}=16

So the volume of the larger cone is <u>16 times greater</u> than the volume of the smaller cone.

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2 years ago
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