Complete question :
Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?
Answer:
61
Step-by-step explanation:
Given the following :
Total number of students = 4 + 1 missing = 5
Score on the four avaliable papers = 60, 62, 56, 57
Average score of the 5 papers = 59.2
Score on missing paper :
Sum of each score / number of papers
Sum of each score = sum of available scores + missing score
Let missing score = m
(60 + 62 + 56 + 57 + m) = 235 + m
Recall:
Average = total sum / number of observations
Hence,
59.2 = (235 + m) / 5
59.2 × 5 = 235 + m
296 = 235 + m
m = 296 - 235
m = 61
Missing score = 61
(this is for fractions!!!!!!!!!!!!) 28/5 or 5 3/5
i think u just make it into 5.6/1 multiply by 10 which gets 56/10 and wala
but it's not simplified. 56 and 10 is divisible by 2 so u get 28/5 which is actually 5 3/5 (which is 5.6!!)
Answer:
Step-by-step explanation:
The directrices in this case are vertical lines, so we have a horizontal ellipse. The equation for that ellipse is:
The center of the ellipse is (h,k), the diretrix is x = d and the foci are given by (h+c, k) and (h-c, k)
So, comparing the foci, we have that k = 0 and:
Adding these two equations, we have:
We can find the value of a^2 using the property:
Using c = 2 and d = 4, we have:
Now, to find b^2, we use the property:
So the equation of the ellipse is:
Answer:
800,000,000 90,000,000 5,000,000 3,000 40 9
Step-by-step explanation:
