Answer: ![\sqrt[6]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B2%7D)
Step-by-step explanation:
You know that the expression is ![\frac{\sqrt{2}}{\sqrt[3]{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D)
By definition we know that:
![\sqrt[n]{a}=a^{\frac{1}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D)
You also need to remember the Quotient of powers property:

Therefore, you can rewrite the expression:

Finally, you have to simplify the expression. Therefore, you get:
![=2^{(\frac{1}{2}-\frac{1}{3})}\\=2^{\frac{1}{6}}\\=\sqrt[6]{2}](https://tex.z-dn.net/?f=%3D2%5E%7B%28%5Cfrac%7B1%7D%7B2%7D-%5Cfrac%7B1%7D%7B3%7D%29%7D%5C%5C%3D2%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%5C%5C%3D%5Csqrt%5B6%5D%7B2%7D)



Graph is the picture which represents the relation between two parameters.
Infinity values of one entity gives respected value of another entity.
Every graph has methemetical equation. Holding above sentences.
example:


Etc.
Answer:
-3.33 ft. per second
Step-by-step explanation:
The rate of change of an object can be calculated by finding the difference in position between the starting point and end point, and then dividing by the difference in time between the starting time and end time. Using the values provided in the question we can calculate the following
= 3.33 ft. per second
With the calculation above we can see that the rate of change during these 15 seconds is 3.33 ft. per second. Since the endpoint is further down below ground level then we were descending which means that the rate of change would be a negative (-3.33 ft. per second)
The answer to this question is letter a
A) y = 5/3x - 9
B) y = -x + 3
C) y = -2/7x + 1
D) y = 5x + 4