Answer:
100%
Explanation:
No matter how many factors are in the cross, if an 2 purebred (homozygous individuals) are crossed, (one dominant, one recessive) the dominant phenotype will always be displayed.
Imagine a cross with between two individuals true breeding for 6 traits. One shows all dominant genotypes, one shows all recessive genotypes. The only gametes those individuals can pass on will always produce heterozygotes.
AABBCCDDEEFFGG x aabbccddeeffgg
The first individual can only give ABCDEFG alleles. The second individual can only give abcdefg alleles. Therefore, all offspring will be AaBbCcDdEeFfGg, and will therefore express the dominant trait.
Answer:
The world climate would drastically change.
Explanation:
- First off, both poles would have rapid expansion, with the freezing of more water near the poles.
- Many species of trees and plants would die out in certain areas, since they tend to be in their ideal locations, so the change in climate will make the northern parts of many habitats destroyed.
- Deserts would expand and the average temperature would rise.
- Also, many animals would also die out, because of the change in their environments.
- Conifers would shift southward, causing many forests / parts of forests to turn into wastelands, causing the earth's oxygen production to decrease.
Since the other answer got deleted, i'll just answer it for you.
a sinoatrial node is the main pacemaker that begins each heartbeat located in the junctions of superior vena cava and the right atrium. It signals from the node that spread through the atria and determines the heart rates.
The right answer is A) Trisomy
Aberrant karyotypes containing an abnormal number of chromosomes are known in the human species. The best-known (and most common) chromosomal abnormality is trisomy 21, which is responsible for Down syndrome (mongolism). There are others such as Turner syndrome (woman with a single X chromosome) or Klinefelter syndrome (man XXY).
These abnormalities originate from the non-disjunction of the chromosomes of a pair of homologues during metaphase I of meiosis. At the end of division I, a daughter cell contains the two chromosomes of the pair considered and the other cell does not contain a chromosome of this pair. A similar result can be obtained during a bad distribution of chromatids during anaphase II.
After fertilization from a gamete of this type, a trisomy or a monosomy is obtained.
