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3 years ago

Find the quadratic polynomial whose graph goes through the points (-1,8), (0,6), and (2, 26). f(0) = x^2+ x+

Mathematics

1 answer:

kirill115 [55]3 years ago

8 0

Answer:

4x² + 2x + 6 = 0

Step-by-step explanation:

The polynomial which has highest degree 2 is known as quadratic polynomial. It is of the form:

ax² + bx + c = 0

where, a ≠ 0 and a, b & c are any constant.

We have given three points (-1, 8), (0, 6), and (2, 26)

Putting these value of (x, y) in quadratic equation one by one.

We get, three equations:

8 = a - b + c

6 = c

26 = 4a + 2b + c

Solving these equations, We get,

a = 4, b = 2 and c = 6

Now putting these values of a, b, and c in standard quadratic equation.

We get,

4x² + 2x + 6 = 0

which is required equation.

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Leno4ka [110]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Please help me ASAP! Triangle ABC is located at A (2, 3), B (4, 4), and C (6, 3). Zackary says that triangle ABC is an isosceles

son4ous [18]

<h2>Hello!</h2>

The answer is:

The second option,

Zackery, because AB=BC

To identify which type of triangle is the triangle formed by the given points, first, we need to calculate the distance between the points.

So, finding the distances we have:

From A to B: (2,3) and (4,4)

$distance=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}\\\\distance=\sqrt{(4-2)^{2} +(4-3)^{2}}=\sqrt{2^{2} +1^{2} }=\sqrt{4+1}=\sqrt{5}=2.24units$

From B to C: (4,4) and (6,3)

$distance=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}\\\\distance=\sqrt{(6-4)^{2} +(3-4)^{2}}=\sqrt{2^{2} +(-1)^{2} }=\sqrt{4+1}=\sqrt{5}=2.24units$

Hence, since the distances AB and BC are equal, the triangle is an isosceles triangle, so the answer is:

Zackery, because AB=BC

Have a nice day!

7 0

3 years ago

Please answer and explain how you did it.

alukav5142 [94]

Refer to the attached image.

Given: $m \angle A = 65^\circ$ and measure of exterior angle at C = $117^\circ$ .

We have to determine the measure of angle B and angle BCA.

By applying exterior angle property of the triangle which states:

"An exterior angle of a triangle is equal to the sum of the opposite interior angles".

So, exterior angle C = $m \angle A + m \angle B$

$117^\circ = 65^\circ+ m \angle B$

$m \angle B = 52^\circ$

Now, applying angle sum property in triangle ABC which states:

"The sum of all the angles of a triangle is 180 degrees".

$m \angle A + m \angle B + m \angle BCA = 180^\circ$

$65^\circ + 52^\circ + m \angle BCA = 180^\circ$

$117^\circ + m \angle BCA = 180^\circ$

$m \angle BCA = 180^\circ - 117^\circ$

$m \angle BCA =63^\circ$

Therefore, the measure of $m \angle B = 52^\circ$ and $m \angle BCA =63^\circ$ .

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3 years ago

Which exponential model best represents the data? O f(x) = 3(1.2) O f(x) = 2(0.3)* O f(x) = 2(3)* O f(x) = 3(0.2)*

aleksley [76]

The exponential model has an initial value of 3

The exponential model of the data is f(x) = 3 * (1.2)^x

<h3>How to determine the exponential model?</h3>

From the complete question,we have the following parameters:

Initial value, a = 3
Growth rate, r = 0.2

The exponential model is then calculated as:

f(x) = a * (1 + r)^x

Substitute known values

f(x) = 3 * (1 + 0.2)^x

Evaluate the sum

f(x) = 3 * (1.2)^x

Hence, the exponential model of the data is f(x) = 3 * (1.2)^x

Read more about exponential models at:

brainly.com/question/7296382

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2 years ago

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