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Asymptote at x = 3 and a horizontal asymptote at y = 1. The curves approach these asymptotes but never cross them. The method used to find the horizontal asymptote changes depending on how the degrees of the polynomials in the numerator and denominator of the function compare.
I physically cannot tell you
It is an isosceles triangle
Answer:
<em>17/2, 8.8 with bar on right 8, |-9|, sqrt(82)</em>
Step-by-step explanation:
sqrt(82) = 9.05538...
17/2 = 8.5
8.8 with bar on right 8 = 8.8888888...
|-9| = 9
In order from least to greatest: 17/2, 8.8 with bar on right 8, |-9|, sqrt(82)
