The range of the sprinkler will be the area of a circle with a radius of 40 feet.
area of circle = 
area of circle = 
area of circle = 
= 
answer:
Approximately 0.3246 (rounded to the nearest ten thousandth). Find the square root of 40, then subtract 6.
The situation which is not possible about the pencils in her box is; Choice B: The longest pencil in the box is 8cm long.
<h3>Mean and Measure of central tendency</h3>
By convention, the mean is a statistical measure of central tendency.
On this note, if the mean of a set of data values is 10, this means the data values have data points greater, equal and less than the mean value.
- On this note, it is impossible to have the longest pencil in the box to have a length, 8cm.
Read more on Mean;
brainly.com/question/281308
Hello from MrBillDoesMath!
Answer: N = 143
Discussion:
This one took some trial and error! At first I listed all 2 digit primes, looked at the list, but didn't know how to proceed. So, I took the smallest 2 digit primes numbers: 11 and 13 and wondered if their product, 13*11 = 143, could be represented as the sum of 3 consecutive primes. I went back to my list of primes, added groups of three consecutive numbers that seemed to be in the right range to give the desired sum, and stumbled on 43, 47, and 53!
43 + 47 + 53 = 143 !
Therefore N = 143. It's the sum of 43, 47, and 53 as well as the product of 11 and 13.
Thank you,
MrB
Answer:14708
Step-by-step explanation:Exponential Functions:
y=abxy=ab^x this is not right not correct
y=ab
x
a=starting value = 13000a=\text{starting value = }13000
a=starting value = 13000
r=rate = 2.5%=0.025r=\text{rate = }2.5\% = 0.025
r=rate = 2.5%=0.025
Exponential Growth:\text{Exponential Growth:}
Exponential Growth:
b=1+r=1+0.025=1.025b=1+r=1+0.025=1.025
b=1+r=1+0.025=1.025
Write Exponential Function:
y=13000(1.025)xy=13000(1.025)^x
y=13000(1.025)
x
Put it all together
Plug in time for x:\text{Plug in time for x:}
Plug in time for x:
y=13000(1.025)5y=13000(1.025)^{5}
y=13000(1.025)
5
y=14708.30677y= 14708.30677
y=14708.30677
Evaluate
y≈14708y\approx 14708
y≈14708
