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klasskru [66]
3 years ago
9

PLEASE HELP! What's 4 3/10 - 80/100

Mathematics
2 answers:
____ [38]3 years ago
8 0
The answer is 3.5. Look above for step by step answer
Citrus2011 [14]3 years ago
7 0

Answer:

Step-by-step explanation:

4\frac{3}{10} -\frac{80}{100} =\frac{43}{10} -\frac{8}{10} \\                                             =\frac{35} {10} \\                                             =3.5

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( p + 6 ) + ( 8p + 2 )
victus00 [196]

Answer:

9p+8

Step-by-step explanation:

p+8p= 9p

6+2= 8

9p+8

4 0
2 years ago
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Read the following statement.
nekit [7.7K]
Bro... ahahaha the answer is D DDDDDDDDDDDDDDD peace man 

8 0
3 years ago
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Write an equation for this trend line
jeka94

Answer:

y=-1/3x+8 i think

Step-by-step explanation:

3 0
3 years ago
Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop
xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

 f(x)=log (3 x) +5 x²

f'(x)=\frac{1}{3x}+10 x

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

  x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248

x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012

x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057

x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052

So, root of the equation =0.205 (Approx)

Approximate relative error

                =\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41

 Approximate relative error in terms of Percentage

   =0.41 × 100

   = 41 %

7 0
3 years ago
The mean sat verbal score is 486, with a standard deviation of 95. use the empirical rule to determine what percent of the score
Pavel [41]
Find the z-scores for the two scores in the given interval.

z=\frac{x-\mu}{\sigma}

For the score x =391, z=\frac{391-486}{95}=\frac{-95}{95}=-1.

For the score x = 486, z=\frac{486-486}{95}=0

Now you want the area (proportion of data) under the normal distribution from z = -1 to z = 0. The Empirical Rule says that 68% of the data falls between z = -1 to z = 1. But the curve is symmetrical around the vertical axis at z = 0, so the answer you want is HALF of 68%.

8 0
3 years ago
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