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3 years ago

PLEASE HELP!!! One step equation... solve by division b/7=5

Mathematics

2 answers:

Svetlanka [38]3 years ago

6 0

Answer:

multiply both side of the equation by 7.

7 x b/7 = 7 x 5

cancel common factor of 7

b = 7 x 5

b = 35

tresset_1 [31]3 years ago

4 0

Answer:

b = 35

Step-by-step explanation:

$\frac{b}{7} =5\\Multiply\: through\: by\: 7\\\\7(\frac{b}{7} ) =5\times 7\\\\b = 35$

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2 years ago

The cost for a pack of 24 pens is $4.08 . Find the unit price in dollars per pen. If necessary, round your answer to the nearest

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3 years ago

In how many years will the interest of a sum of rs 3600 at the rate of 5.5% per year be rs 594?

boyakko [2]

Answer:

In 3 years, the interest of a sum of rs 3600 at the rate of 5.5% per year be Rs 594.

Step-by-step explanation:

T = ?

R = 5.5%

P = Rs 3600

I = Rs 594

T = (I×100)/(P×R)

or, T = (594×100)/(3600×5.5)

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7 0

2 years ago

A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?

kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

$f(x)=\frac{1}{2^{2x}}$ (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

$\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]$ (2)

To solve this derivative you use the following derivative formula:

$\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}$

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

$\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)$

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

$-2(ln2)2^{-2x}=-1$

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

$-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235$

With this value you calculate f(a):

$f(a)=\frac{1}{2^{2(0.235)}}=0.721$

Next, you use the general equation of line:

$y-y_o=m(x-x_o)$

for xo = a = 0.235 and yo = f(a) = 0.721:

$y-0.721=(-1)(x-0.235)\\\\y=-x+0.956$

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

$0=-x+0.956\\\\x=0.956$

hence, the x-intercept of the tangent line is 0.956

5 0

2 years ago