Answer:
Since b^2 -4ac = 256 we have 2 real distinct root roots
Step-by-step explanation:
4x^2+12x=7
We need to subtract 7 to get it in the proper form
4x^2+12x-7=7-7
4x^2+12x-7=0
The discriminant is b^2 -4ac
when the equation is ax^2 +bx+c
so a =4 b=12 and c=-7
(12)^2 - 4(4)(-7)
144 +112
256
If b^2 -4ac > 0 we have 2 real distinct roots
If b^2 -4ac = 0 we have one real root
If b^2 -4ac < 0 we have two complex root
Since b^2 -4ac = 256 we have 2 real distinct root roots
It depend on what problem you have
Answer:
Step-by-step explanation:
a₆ = a₇+(6-7)d = -4 -(-5) =1
My guess would be distributive. i maybe be wrong so don't get mad if I'm wrong.
102 because it’s kind of like a 180 but not I’m direct form
