The area would be 132cm^2 (squared)
(9x4)x2+(7+8)x4 =132
The perimeter you just add everything up so it’s 65cm
15+13+4+7+9+4+13
Answer:
A stone is thrown straight up from the edge of a roof, 750 feet above the ground at a speed of 14 feet per second. A) Remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 2 seconds later? B) At what time does the stone hit the ground? C) What is the velocity of the stone when it hits the ground?
Step-by-step explanation:
A stone is thrown straight up from the edge of a roof, 750 feet above the ground at a speed of 14 feet per second. A) Remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 2 seconds later? B) At what time does the stone hit the ground? C) What is the velocity of the stone when it hits the ground?
Answer: (-2y+3)(y+11)
Step-by-step explanation:
33 is 3×11 so expect something like
(y+3)(y+11) = y^2+14y+33
leading term has coefficient -2 so
one factor is like (-2y+__)
Try (-2y+3)(y+11) = -2y^2-19y+33
which happens to be the answer
Answer:
Width=6.5 cm
Length=12 cm
Step-by-step explanation:
Step 1: Express the lengths and widths
Width=w
Length=l, but 1 cm less than twice the width=(2×w)-1=2 w-1
Step 2: Solve for the length and width
A=L×W
where;
A=area of the photograph
L=length of the photograph
W=width of the photograph
In our case;
A=91 cm²
L=2 w-1
W=w
91=(2 w-1)w
2 w²-w=91
2 w²-w-91=0, is a quadratic equation
solve for w
w={-1±√(-1²-4×2×-91)}/(2×2)
w=(-1±27)/4
w=(27-1)/4=6.5, or (-1-27)/4=-8
Take w=6.5 cm
L=(2×6.5)-1=13-1=12 cm
Width=6.5 cm
Length=12 cm
