What you find the area of the following parallelogram, what units should you use?

Which of the following equations below is a linear inequality?

Ket [755]

Answer:

D

Step-by-step explanation:

A linear inequality is an inequality which involves a linear function. A linear inequality contains one of the symbols of inequality: <, >, ≤, ≥.

Consider all options:

A. The inequality $\dfrac{y}{x}>3\cdot x+2$ is not linear linear inequality, because x is in the left part denominator and in the right part numerator.

B. This option shows linear equation, not inequality.

C. This option shows quadratic equation, not linear inequality.

D. This option shows linear inequality $y\le 5x-5$

4 0

3 years ago

the vertex of this parabola is at (2,-1). when the y-value is 0, the x-value is 5. what is the coefficient of the squared term i

timama [110]

We know that

case a)
the equation of the vertical parabola write in vertex form is
y=a(x-h)²+k,
where (h, k) is the vertex.

Using our vertex, we have:
y=a(x-2)²-1
We know that the parabola goes through (5, 0),

so
we can use these coordinates to find the value of a:
0=a(5-2)²-1
0=a(3)²-1
0=9a-1

Add 1 to both sides:
0+1=9a-1+1
1=9a
Divide both sides by 9:
1/9 = 9a/9
1/9 = a
y=(1/9)(x-2)²-1

the answer is
a=1/9

case b)
the equation of the horizontal parabola write in vertex form is
x=a(y-k)²+h,
where (h, k) is the vertex.

Using our vertex, we have:
x=a(y+1)²+2,
We know that the parabola goes through (5, 0),

so
we can use these coordinates to find the value of a:
5=a(0+1)²+2
5=a+2
a=5-2
a=3
x=3(y+1)²+2

the answer is
a=3

see the attached figure