Answer:
Pipe Q
Step-by-step explanation:
Two pipes p and Q fill a water tank. Each pipe fills the tank with water at a constant rate. Pipe P fills the tank with 20 gallons of water in 4 minutes. The equation in equals n = 6t shows the number of gallons of water n with which pipe Q fills the tank in t minutes. Which pipe fills the tank with more water each minute and by how much
Solution:
Pipe P fills the tank with 20 gallons of water in 4 minutes. If n represent the number of gallons of water that fills the tank in t minutes, then for pipe P:
n = 20 gallons / 4 minutes *t
n = 5t
Also, the number of gallons of water that fills the tank in t minutes for pipe Q is given by:
n = 6t
Since the rate at which pipe Q fills the tank (i.e. 6t) is greater than the rate at which pie P fills the tank (i.e. 5t), hence Pipe P fills the tank with more water each minute by 6 gallons while pipe P fills by 5 gallons each minute.
They are corresponding angles because they are in the same spot on either side of the parallel lines.
<span>The probability that a house in an urban area will develop a leak is 55%. if 20 houses are randomly selected, what is the probability that none of the houses will develop a leak? round to the nearest thousandth.
Use binomial distribution, since probability of developing a leak, p=0.55 is assumed constant, and
n=20, x=0
and assuming leaks are developed independently between houses,
P(X=x)
=C(n,0)p^x* (1-p)^(n-x)
=C(20,0)0.55^0 * (0.45^20)
=1*1*0.45^20
=1.159*10^(-7)
=0.000
</span>
Answer:
60 pages
Step-by-step explanation:
Day 1 : 1/3 book
Day 2: 1/4 book
Day 3: 1/5 book
Day 4: 13 pages
Total days 1 through 3 = 1/3 + 1/4 + 1/5 = 20/60 + 15/60 + 12/60 = 47/60
Day 4 = 1 - 47/60 = 13/60
The value of the car is January 2003 is $199,148.54.
<h3>What is the value of the car?</h3>
Depreciation is the rate of decline in the value of an asset with the passage of time.
The exponential equation that can be used to determine the value of the car is:
Value of the car = purchase value(1 - rate of decline)^time
400,000 x (1 - 0.16)^(2003 - 1999)
400,000 x (0.84^4) = $199,148.54
To learn more about depreciation, please check: brainly.com/question/15085226
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