372 is the answer.
(9*6*3)+(10*7*3)=372
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Suppose that equation of parabola is
y =ax² + bx + c
Since parabola passes through the point (2,−15) then
−15 = 4a + 2b + c
Since parabola passes through the point (-5,-29), then
−29 = 25a − 5b + c
Since parabola passes through the point (−3,−5), then
−5 = 9a − 3b + c
Thus, we obtained following system:
4a + 2b + c = −15
25a − 5b + c = −29
9a − 3b + c = −5
Solving it we get that
a = −2, b = −4, c = 1
Thus, equation of parabola is
y = −2x²− 4x + 1
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Rewriting in the form of
(x - h)² = 4p(y - k)
i) -2x² - 4x + 1 = y
ii) -3x² - 7x = y - 11
(-3x² and -7x are isolated)
iii) -3x² - 7x - 49/36 = y - 1 - 49/36
(Adding -49/36 to both sides to get perfect square on LHS)
iv) -3(x² + 7/3x + 49/36) = y - 3
(Taking out -3 common from LHS)
v) -3(x + 7/6)² = y - 445/36
vi) (x + 7/6)² = -⅓(y - 445/36)
(Shifting -⅓ to RHS)
vii) (x + 1)² = 4(-1/12)(y - 445/36)
(Rewriting in the form of 4(-1/12) ; This is 4p)
So, after rewriting the equation would be -
(x + 7/6)² = 4(-⅛)(y - 445/36)
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I hope this is what you wanted.
Regards,
Divyanka♪
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Answer:
B
Step-by-step explanation:
Answer:
5x + 4y + 12 = 0
Step-by-step explanation:
Start with the point-slope equation of a straight line: y - k = m(x - h):
Here we are given the point (h, k): (-8, 7) and the slope m = -5/4. Inserting this info into the equation give above, we get: y - 7 = (-5/4)(x + 8).
We must put this equation into "standard form" Ax + By + C = 0.
Multiply all three terms by 4 to remove fractions: 4y - 28 = -5(x + 8), or
4y - 28 + 5x + 40 = 0
Rearranging these terms, we get 5x + 4y + 12 = 0, which is the desired equation in standard form.
