All categories

3 years ago

What two numbers multiply to equal 10 but add to equal 6

Mathematics

1 answer:

faltersainse [42]3 years ago

4 0

Its 2 and 5 because 2x5=10

You might be interested in

a roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decora

Arada [10]

Answer:

The mass of each passenger is 550 kg.

The mass of front decoration is 200 Kg.

Step-by-step explanation:

Given : A roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decoration and only 4 passenger cars, it has a mass of 2400 kg.

To find : What is the mass of the decoration and of each passenger car?

Solution :

Let the mass of each passenger is x.

Let the mass of front decoration is y.

When the number of passenger = 6

Mass of 6 passengers and front decoration = 3500 kg.

The equation form is $6x+y=3500$ ..........[1]

When the number of passengers = 4

Mass of 4 passengers and front decoration = 2400 kg.

The equation form is $4x+y=2400$ ........[2]

Solving equation [1] and [2]

Subtract equation [2] from [1],

$6x+y-4x-y=3500-2400$

$2x=1100$

$x=550$

Put value in [1],

$6(550)+y=3500$

$3300+y=3500$

$y=200$

Therefore, The mass of each passenger is 550 kg.

The mass of front decoration is 200 Kg.

8 0

4 years ago

Solve the literal equation for the given variable<br> n =4/5(m+7); m

Step2247 [10]

Answer:

Step-by-step explanation:

First of all multiply both sides by 5

That's

<h3> $5n = 5 \times \frac{4}{5} (m + 7) \\ 5n = 4(m + 7)$ </h3>

<u>Next divide both sides by 4</u>

That's

$m + 7 = \frac{5n}{4}$

Subtract 7 from both sides to make m stand alone

We have

We have the final answer as

Hope this helps you

7 0

3 years ago

Factorise tis please.<br> <img src="https://tex.z-dn.net/?f=%20%28x%2B3%29%5E%7B2%7D%20%2B2%28x%2B3%29" id="TexFormula1" title="

Otrada [13]

$\displaystyle \boxed{(a+b)=a^2+2ab+b^2} \\ \\ (x+3)^2+2(x+3)= \\ x^2+2 \cdot x \cdot 3 +3^2+2x+6 = \\ x^2+6x+9+2x+6= \\ x^2+8x+15= \\ \\ \Delta= b^2-4ac \\ \Delta=8^2-4 \cdot1 \cdot15 \\ \Delta=64-60=4 \\ \\ \\ X_{1,2}= \frac{-b\pm \sqrt{\Delta} }{2a} = \frac{-8\pm2}{2} = \\ \\X1=5 \\ X2=3$