1. =0 2. =2 3. =€0 4. =-5,5 5. =2
Step-by-step explanation:
Consider the LHS, after the 5th step, consider the RHS





Consider the RHS





Answer: 0.8313
Step-by-step explanation:
As per given we have,

Also, the distribution of the number of suitcases that get lost each week on a certain route is approximately normal.
Since , 
z-score corresponds to x= 10:
z-score corresponds to x= 20:
P-value = 

Hence, the probability that during a given week the airline will lose between 10 and 20 suitcases = 0.8313
Answer:
C. x < 25 and x ≥ 0
Step-by-step explanation:
Fastest and easiest way to do this is to graph the inequality and find out the lines.