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Gala2k [10]
2 years ago
5

Chen buys 4 tickets to a soccer game. The total cost before taxes is $80. Which equation would you use to determine the price, p

, of the ticket? A 4p=80 B 80p=4 C 4+p=80 D p/4=80
Mathematics
2 answers:
Assoli18 [71]2 years ago
7 0

Answer:

A. 4p=80

Step-by-step explanation:

Total Cost of 4 tickets=$80

Price=p

Quantity=4

Total cost=price×quantity

80=p×4

80=4p

80=4p is the equation that can be used to determine price

From the equation

80=4p

Divide both sides by 4

80/4=4p/4

20=p

Price is $20 per ticket

DENIUS [597]2 years ago
6 0

Answer:

4p = 80

Step-by-step explanation:

Total cost before tax = $80

Number of tickets purchased = 4

Price 'p' of each ticket

p = total price of ticket / number of tickets purchased

p = 80 / 4

Multiplying both sides by 4

4p = 80

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Step-by-step explanation:

To add or subtract two complex numbers, just add or subtract the corresponding real and imaginary parts. For instance, the sum of 4 -4i and 3 - 2i is 7 -6i. The numbers in standard form will be a + bi, where a is the real part and bi is the imaginary part.

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A number is at most 45
SSSSS [86.1K]

Step-by-step explanation:

Atmost means less than 45:

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7 0
3 years ago
The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f
WITCHER [35]

Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

r=12\ cm\\b=12\ cm\\h=12\ cm

substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r

substitute the given values

C=\frac{1}{2}\pi (12)\\C=6\pi\ cm

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm

simplify

AC=12\sqrt{2}\ cm

Find the perimeter

P=(6\pi+12\sqrt{2})\ cm

simplify

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4 0
3 years ago
Evaluate : -80 - (-15) =
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Answer:

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Step-by-step explanation:

-80 - -15

Two minuses become plus

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Subtract and keep the sign of the higher number

= -(80-15)

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6 0
3 years ago
Read 2 more answers
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