Answers and explanations:
87. The domain of added functions includes the restrictions of both. So the range of the added function in this question is [-4, 3]
88. When finding the domain of a divided function we do the same as adding, but with an extra rule: g can't equal zero. So for this question the domain is (-4, 3)
89. To graph f + g you add the y-values for each x-value. I added a picture to help explain this one!
1 cm = 10 mm
1 cm^2 = 100 mm^2
0.6 cm^2 = 0.6 * 100 mm^2 = 60 mm^2
Let

. Then

, and so as

, you have

. The limit is then equivalent to
it will take 1.33 hours for Braydon and Lauren to get to the same mile marker on the path in the park .
<u>Step-by-step explanation:</u>
Here we have , Braydon can run at 3 miles per hour , he's initially at 10 mile marker . Lauren is at the 12-mile marker at the park, She is walking at a pace of 1.5 miles per hour. We need to find How long will it take for Braydon and Lauren to get to the same mile marker on the path in the park .Let's find out:
Let after time t they meet each other so , Braydon can run at 3 miles per hour , he's initially at 10 mile marker . Distance traveled is given by :
⇒ 
Now , Lauren is at the 12-mile marker at the park, She is walking at a pace of 1.5 miles per hour , Distance traveled is given by :
⇒ 
Equating both we get :
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , it will take 1.33 hours for Braydon and Lauren to get to the same mile marker on the path in the park .
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corresponds to TR. correct option b.
<u>Step-by-step explanation:</u>
In the given parallelogram or rectangle , we have a diagonal RT . We need to find which side is in correspondence with side/Diagonal RT of parallelogram URST .
<u>Side TU:</u>
In triangle UTR , we see that TR is hypotenuse and is the longest side among UR & TU . So , TR can never be equal in length to UR & TU . So there's no correspondence of Side TU with RT.
<u>Side TR:</u>
Since, direction of sides are not mentioned here , we can say that TR & RT is parallel & equal to each other . So , TR is in correspondence with side/Diagonal RT of parallelogram URST .
<u>Side UR:</u>
In triangle UTR , we see that TR is hypotenuse and is the longest side among UR & TU . So , TR can never be equal in length to UR & TU . So there's no correspondence of Side UR with RT.