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Verdich [7]
3 years ago
13

105/6x-1+91/6x-9 simplify equation

Mathematics
1 answer:
saw5 [17]3 years ago
8 0

Answer:

2 (49x - 15)/3

Step-by-step explanation:

You might be interested in
Do you compare a negative decimal to a positive decimal?
Anika [276]

Answer:

Positive: Decimals are a part of a whole just like fractions are a part of a whole. Therefore, a positive decimal is always greater than a negative decimal.

Negative: When you have two negative decimals, the one closer to zero is always greater. The farther a negative decimal is from zero, the smaller its value.

All of it put together (same text as above):

Decimals are a part of a whole just like fractions are a part of a whole. Therefore, a positive decimal is ALWAYS greater than a negative decimal. When you have two negative decimals, the one closer to zero is always greater. The farther a negative decimal is from zero, the smaller its value.

5 0
3 years ago
If r and s are positive integers, is \small \frac{r}{s} an integer? (1) Every factor of s is also a factor of r. (2) Every prime
Yuri [45]

Answer:

<em>If statement(1) holds true, it is correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em>If statement(2) holds true, it is not necessarily correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em></em>

Step-by-step explanation:

Given two positive integers r and s.

To check whether \small \frac{r}{s} is an integer:

Condition (1):

Every factor of s is also a factor of r.

r \geq s

Let us consider an example:

s = 5^2 \cdot 2\\r = 5^3 \cdot 2^2

\dfrac{r}{s} = \dfrac{5^3\cdot2^2}{5^2\cdot2} = 10

which is an integer.

Actually, in this situation s is a factor of r.

Condition 2:

Every prime factor of <em>s</em> is also a prime factor of <em>r</em>.

(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)

Let

r = 2^2\cdot 5\\s =2^4\cdot 5

\dfrac{r}{s} = \dfrac{2^3\cdot5}{2^4\cdot5} = \dfrac{1}{2}

which is not an integer.

So, the answer is:

<em>If statement(1) holds true, it is correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em>If statement(2) holds true, it is not necessarily correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em></em>

8 0
3 years ago
There are 15 people on a basketball team, and the coach needs to choose 5 to put into
snow_lady [41]

Answer:

The coach can do this in 3,003 ways

Step-by-step explanation:

Here, the coach needs to select a team of 5 from a total of 15 players

Mathematically, the number of ways this can be done is simply 15 C5 ways

Generally, if we are to select a number of r items from n items, this can be done in nCr ways = n!/(n-r)!r!

Applying this to the situation on ground, we have;

15C5 = 15!/(15-5)!5! = 15!/10!5! = 3,003 ways

3 0
3 years ago
How would i solvd this problem as sn improper fraction 2 1/8
zmey [24]
17/8..........................................
7 0
2 years ago
Read 2 more answers
If c – 8 is an odd integer, which of the following could be the value of c?
finlep [7]

Answer:

Since you didn't give me any choices I can tell you that c is ANY ODD NUMBER THAT EXISTS.

Step-by-step explanation:

im smart ツ

7 0
2 years ago
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