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romanna [79]
3 years ago
8

What is the answers

Mathematics
1 answer:
LenKa [72]3 years ago
3 0

If x=5 the answer is 0

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28 patients for 2 nurses
alukav5142 [94]
14 patients for each nurse
6 0
3 years ago
What is the simplified form of 5 square root x^4 • 5 square root x^4
laiz [17]

Answer: C

Step-by-step explanation:

You can write each term into a fraction.

\sqrt[5]{x^4} becomes x^4^/^5

When you multiply 2 terms with the same base, you add the exponents.

x^4^/^5*x^4^/^5=x^4^/^5^+^4^/^5=x^8^/^5

x^8^/^5 is also the same as x\sqrt[5]{x^3}

You get this because \sqrt[5]{x^8} =\sqrt[5]{x*x*x*x*x*x*x*x}. When you pull out 5 os x, you are left with x³ on the inside.

8 0
3 years ago
Assume that a simple random sample has been selected from a normally distributed population. State the hypotheses, find the test
BaLLatris [955]

Solution

Hypotheses:

- The population mean is 132. In order to test the claim that the mean is 132, we should check for if the mean is not 132.

- Thus, the Hypotheses are:

\begin{gathered} H_0:\mu=132 \\ H_1:\mu\ne132 \end{gathered}

Test statistic:

- The test statistic has to be a t-statistic because the sample size (n) is less than 30.

- The formula for finding the t-statistic is:

\begin{gathered} t=\frac{\bar{X}-\mu}{\frac{s}{\sqrt{n}}} \\  \\ where, \\ \bar{X}=\text{ Sample mean} \\ \mu=\text{ Population mean} \\ s=\text{ Standard deviation} \\ n=\text{ Sample size} \end{gathered}

- Applying the formula, we have:

\begin{gathered} t=\frac{137-132}{\frac{14.2}{\sqrt{20}}} \\  \\ t=\frac{5}{3.1752} \\  \\ t\approx1.5747 \end{gathered}

Critical value:

- The critical value t-critical, is gotten by reading off the t-distribution table.

- For this, we need the degrees of freedom (df) which is gotten by the formula:

\begin{gathered} df=n-1 \\ df=20-1=19 \end{gathered}

- And then we also use the significance level of 0.1 and the fact that it is a two-tailed test to trace out the t-critical. (Note: significance level of 0.1 implies 10% significance level)

- This is done below:

- The critical value is 1.729

P-value:

- To find the p-value, we simply check the table for where the t-statistic falls.

- The t-statistic given is 1.5747. We simply check which values this falls between in the t-distribution table. It falls between 1.328 and 1.729. We can simply choose a value between 0.1 and 0.05 and multiply the result by 2 since it is a two-tailed test.

- However, we can also use a t-distribution calculator, we have:

- Thus, the p-value is 0.13183

Final Conclusion:

- The p-value is 0.13183, and comparing this to the significance level of 0.1, we can see that 0.13183 is outside the rejection region.

- Thus, the result is not significant and we fail to reject the null hypothesis

7 0
1 year ago
What is the greatest common factor of 24 and 84? A. 6 B. 12 C. 20 D. 24
sladkih [1.3K]

The greatest common factor for these two numbers is 6 because if you divide 24 by 6 you get 4 and if you divide 84 by 6 you get 14.

8 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST ANSWER TO WHOEVER ANSWERS FIRST AND CORRECT
Yanka [14]

Answer:

<h2>12.56</h2>

Step-by-step explanation:

2 x 2 x 3.14 = 12.56

<em>PLEASE MARK BRAINLIEST</em>

7 0
3 years ago
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