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maks197457 [2]
3 years ago
8

Acell phone company charges $40 per month for unlimited calling, and $0.20 per text message sent. If t represents

Mathematics
1 answer:
-Dominant- [34]3 years ago
3 0

Answer:  40 + 0.21t

Step-by-step explanation:

If t is the number of texts last month and the initial fee for each month is $40  then you will have the expression 40+0.21t

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Answer:

equivalent ratio for this question is

4:6:48

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Is 0.09 squared a rational number?
Novay_Z [31]
Yes, 0.09 squared, or <span>0.0081, is a rational number.</span>
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PLEASE HELP ITS DUE IN LIKE30 min !!!!!!!!!Give the following functions f(x) and g(x),solve (f/g) (-5) and select the correct an
Bingel [31]

Answer:

The answer is -32

Step-by-step explanation:

g(-5) = (-5)-1= -6

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4 years ago
If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)
sweet-ann [11.9K]

Answer:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

Step-by-step explanation:

Given

tan\theta = 3

Required

Find

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)

Calculate tan(\theta + \pi) \ and\ tan(\theta+2\pi)

Using tan rule

tan(\theta + \pi)  = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}

So:

tan(\theta + \pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + \pi)  = \frac{tan\theta}{1 }

tan(\theta + \pi)  = \tan\theta

tan(\theta+2\pi)

tan(\theta + 2\pi)  = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}

tan(\theta + 2\pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + 2\pi)  = \tan\theta'

'So:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = tan\theta +tan\theta +tan\theta

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

4 0
3 years ago
Please choose the answer that describes the scientific notation for 3,134,000,000
topjm [15]

Answer:

= 3.134 × 10^9

(scientific notation)

= 3.134e9

(scientific e notation)

= 3.134 × 10^9

(engineering notation)

(billion; prefix giga- (G))

= 3134000000

(real number)

Step-by-step explanation:


6 0
3 years ago
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