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olga2289 [7]
1 year ago
7

Sinª A cosec² A+ cos4 A sec² A = 1

Mathematics
1 answer:
12345 [234]1 year ago
4 0

Step-by-step explanation:

sin4Acosec2A+cos4Asec2A=sin2Asin4A+cos2Acos4A=sin2A+cos2A=1

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In the last year, U.S. car sales of all makes and models have dropped by 16%. Let's say that a car dealer sells 325 cars. If thi
IRINA_888 [86]

Answer:

c. 273 cars

Step-by-step explanation:

First you need to find what 16% of 325 is

325x.16=52

because the number sold dropped by 16% you will subtract 52 from 325

325-52=273

you can also calculate the answer by subtracting 100% by 16%

100%-16%=84%

now you can calculate 84% of 325

325x.84=273

6 0
2 years ago
C= 5/9 (F−32)
Grace [21]

Answer:

C = 5/9 (F - 32)

This is a temperature scale change comparison.

By this we understand, that ,

1°C = 5/9°F

Which is equal to, 5/9°F = 1°C

These two statements are satisfied by I. and II.

So, the correct answers are, I. and II.

If my answer helped, kindly mark me as the brainliest!

Thank You!!

5 0
3 years ago
What else would need to be congruent to show that ABC = PQR by sss
Katen [24]
Ab=pq
qr= bc
and so on
7 0
3 years ago
99. What is the greatest prime factor of 5,355?<br> A. 17<br> B. 51<br> C. 119<br> D. 131<br> E. 153
NemiM [27]
Hello,

5355 is divisble by 3 since 5+3+5+5=18 is divisible by 3
5355=3*1785
1785 is divisble by 3 since 1+7+8+5=21 is divisible by 3
1785=3*595
595 is not divisible by 3 but by 5
595=5*119
119 is divisible by 7 since 1*2+1*3+9*1=14 is divisible by 7.
119=7*17

17 is prime
Answer A



8 0
3 years ago
Una piscina rectangular de 15 metros de largo por 9 metros de ancho està rodeada por un
stira [4]

Answer: 2 meters.

Step-by-step explanation:

Let w = width of the cement path.

Dimensions of pool : Length = 15 meters , width = 9 meters

Area of pool = length x width = 15 x 9 = 135 square meters

Along width cement path, the length of region = 2w+15

width = 2w+9

Area of road with pool =  (2w+15) (2w+9)

= 4w^2+30w+18w+135\\\\=4w^2+48w+135

Area of road = (Area of road with pool ) -(area of pool)

\Rightarrow\ 112 =4w^2+48w+135- 135\\\\\Rightarrow\ 112= 4w^2+48w\\\\\Rightarrow\ 4 w^2+48w-112=0\\\\\Rightarrow\ w^2+12w-28=0\ \ \ [\text{Divide both sides by 4}]\\\\\Rightarrow\ w^2+14w-2w-28=0\\\\\Rightarrow\ w(w+14)-2(w+14)=0\\\\\Rightarrow\ (w+14)(w-2)=0\\\\\Rightarrow\  w=-14\ or \ w=2

width cannot be negative, so w=2 meters

Hence, the width of the road = 2 meters.

8 0
3 years ago
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