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Lina20 [59]
3 years ago
6

What is the solution to the system of equations graphed below?

Mathematics
2 answers:
aniked [119]3 years ago
8 0
The answer is a. (2, -3).
GuDViN [60]3 years ago
6 0

Answer:

Its A i just took the test :)

Step-by-step explanation:

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write an equation in slope-intercept form of the line that passes through the points (-2,3) and (2,7)
olga nikolaevna [1]
Your equation is y= x + 5
7 0
3 years ago
In the graph below, Point A represents Owen's house, Point B represents David's house and Point C represents the school. Who liv
ycow [4]

Answer:

• David

,

• 4 miles

Explanation:

In the graph:

The given locations are:

• Owen's House, A(11,3)

,

• David's House, B(15,13)

,

• School, C(3,18)

We determine both Owen's and David's distance from the school using the distance formula.

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Owen's distance from school (AC)

\begin{gathered} AC=\sqrt[]{(3-11)^2+(18-3)^2} \\ =\sqrt[]{(-8)^2+(15)^2} \\ =\sqrt[]{64+225} \\ =\sqrt[]{289} \\ AC=17\text{ miles} \end{gathered}

David's distance from school (BC)

\begin{gathered} BC=\sqrt[]{(3-15)^2+(18-13)^2} \\ =\sqrt[]{(-12)^2+(5)^2} \\ =\sqrt[]{144+25} \\ =\sqrt[]{169} \\ BC=13\text{ miles} \end{gathered}

We see from the calculations that David lives closer to the school, and by 4 miles.

The graph below is attached for further understanding:

5 0
1 year ago
156 divided by 12 equals?
Sergeu [11.5K]
156/12 = 12 * 13/12 = 13 :D
3 0
3 years ago
Read 2 more answers
Polygon CCC has an area of 404040 square units. K 2ennan drew a scaled version of Polygon CCC using a scale factor of \dfrac12 1
nikdorinn [45]

Answer:

<em>Area of polygon D = 10 square units</em>

Step-by-step explanation:

<u>Given:</u>

Polygon <em>C </em>has an area of 40 square units.

It is scaled with a scale factor of \frac{1}2 to form a new polygon D.

<u></u>

<u>To find:</u>

The area of polygon D = ?

<u>Solution:</u>

When any polygon is scaled to half, then all the sides of new polygon are half of the original polygon.

And the area becomes one-fourth of the original polygon.

Let us consider this by taking examples:

  • First of all, let us consider a right angled triangle with sides <em>6, 8 and 10 units.</em>

Area of a right angled triangle is given by:

A = \dfrac{1}{2} \times Base \times Height\\\Rightarrow A = \dfrac{1}{2} \times 6 \times 8 = 24\ sq\ units

If scaled with a factor \frac{1}{2}, the sides will be 3, 4 and 5.

New area, A':

A' =\dfrac{1}{2} \times 3 \times 4 = 6\ sq\ units = \dfrac{1}4\times A

i.e. Area becomes one fourth.

  • Let us consider a rectangle now.

Sides be 8 and 10 units.

Area of a rectangle, A = Length \times Width = 8 \times 10 = 80 sq units.

Now after scaling, the sides will be 4 and 5 units.

New Area, A' = 4 \times 5 =20 sq units

So, \bold{A' = \frac{1}4 \times A}

Now, we can apply the same in the given question.

\therefore Area of polygon D = \bold{\frac{1}{4}}\times Area of polygon C

Area of polygon D = \bold{\frac{1}{4}}\times 40 = <em>10 sq units</em>

4 0
3 years ago
Which set of parametric equations represents the following function y=square root of x+3
Irina18 [472]
The given equation is:

y= \sqrt{x+3}

We have to find, which of the given set of parametric equations given in the options, result in the above equation:

The correct answer would be option A.

The equations in option A are:

x(t) = 5t \\ &#10;y(t)= \sqrt{5t+3}

From first equation we can see that 5t is equal to x. Using the value of 5th in second equation, we get the equation as:

y= \sqrt{x+3}

Therefore, the correct answer is option A
3 0
3 years ago
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