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NeTakaya
3 years ago
11

Given P=1/2x(y+z),find the value of P,if x=6 and y=9 and z=7

Mathematics
1 answer:
GREYUIT [131]3 years ago
8 0
<span>P=1/2 x(y+z)
</span><span>P=1/2 (6)[9 + 7]
P = 3(16)
P = 48

hope it helps</span>
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180 °- 121°

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Explain why dosea mountain climber needs an oxygen supply at very high altitude even through the air still contains 21% oxygen
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2 years ago
Find a ⋅ b. a = &lt;5, 2&gt;, b = &lt;4, 5&gt;
cestrela7 [59]

Answer:

  30

Step-by-step explanation:

For a = <xa, ya> and b = <xb, yb>, the dot product is the sum of products ...

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Substituting the given information, you have ...

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6 0
3 years ago
What is the difference? x+5/x+2-x+1/x2+2x
Mrac [35]

Question

x+5/x+2 - x+1/x²+2x

Answer:

= (x² - 4x - 1)/[x (x+2)]

= (x² - 4x - 1)/[x² + 2x]

Step-by-step explanation:

x + 5/x + 2 - x + 1/x² + 2x

We factorise the second denominator to give us :

x + 5/x + 2 - x + 1/x(x + 2)

We find the L.C.M of both denominators which is x(x+2).

[x(x + 5)-(x + 1)] / (x (x + 2))

Expand the bracket

=[x² +5x - x -1] / [x (x + 2)]

=(x² - 4x - 1) / [x (x + 2)]

= (x² - 4x - 1)/ [x (x + 2)]

= (x² - 4x - 1) / [x² + 2x]

6 0
3 years ago
If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f
nikklg [1K]

The quadratic function given by:


f(x)=a(x-h)^2+k, \ \ \ a\neq 0


is in vertex form. The graph of f is a parabola whose axis is the vertical line x=h and whose vertex is the point (h, k). So:


To translate the graph of a function to the right, left, upward or downward we have:

For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)


By knowing this things, we can solve our problem as follows:


FIRST.

  • Translating <em>11 units to the left:</em>

g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2


  • Then translating<em> 5 units down:</em>

g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5


Since the new function is fatter, the factor we need to multiply the term (x+11)^2 <em>must be</em> less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.


<em>Therefore, the right answer is </em><em>b. f(x) = 1/2(x + 11)^2 - 5</em>


SECOND.

  • Translating <em>8 units to the right:</em>

g(x)=f(x-8) \\ \\ \therefore g(x)=(x-8)^2


  • Then translating<em> 1 unit down:</em>

g(x)=f(x)-c \\ \\ \therefore g(x)=(x-8)^2-1


As explained in the previous case, there are two factors 1/3 and 3, so we choose the first one.


<em>Therefore, the right answer is </em><em>a. g(x) = 1/3(x - 8)^2 - 1</em>

7 0
3 years ago
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