Question

Hallar el menor de tres números consecutivos, si la suma de la mitad del número menor más la tercera parte del número mayor excede en cinco al número de en medio

Answer 1

Answer:

The lowest of three consecutive numbers is $-32$

Step-by-step explanation:

The question in English

Find the lowest of three consecutive numbers, if the sum of one-half of the lowest number plus one-third of the highest number exceeds the middle number by five.

Let

x-----> the lowest consecutive number

x+1-----> the middle consecutive number

x+2-----> the highest consecutive number

$\frac{x}{2}+\frac{x+2}{3}=(x+1)+5$

solve for x

$\frac{x}{2}+\frac{x+2}{3}=(x+1)+5\\ \\ \frac{3x+2x+4}{6}=x+6\\ \\5x+4=6x+36\\ \\6x-5x=4-36\\ \\x=-32$