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zmey [24]
3 years ago
14

Name two ways in which all hydrocarbons are alike?

Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0

<u>Explanation:</u>

All hydrocarbons are considered as organic compounds. Every hydrocarbon has these two conditions, in which it is considered as a hydrocarbon, they are:

  • All the compounds must have carbon and hydrogen atoms in it.
  • There must be covalent bonding between hydrogen and carbon.

If these two conditions are found in any compound, then that compound is considered as a hydrocarbon.

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Hey I need help with this element, compound, and mixtures worksheet
Alika [10]

We should describe a little bit the legend.

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B - Compound - here we may have circles with same or different color bonded together (water or oxygen which is a diatomic molecule).

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D - Mixture of compounds - circles with same or different color bonded together but we should see two or more types of connectivity between circles (mixture of water and ethanol).

E - Mixture of elements and compounds - circles with same or different color bonded together mixed with circles with same color and not bonded together (a mixture between oxygen which is a diatomic molecule and noble gas like argon).

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1) B

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3) D

4) D

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9) E

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3 years ago
Expressed in scientific notation(6.0 x 104) (3.1 x 10-1) =
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3 years ago
You are a NASCAR pit crew member. Your employer is leading the race with 20 laps to go. He just finished a pit stop and has 5.0
jek_recluse [69]

Answer:

Since there are 3500 g of fuel left in the tank, and he needs only 1687.5 g to complete 20 laps, he has enough fuel to complete the race. I will tell the driver that he does not need to make another pit stop as he has enough fuel to complete the race.

Explanation:

Density = mass / volume

Density of fuel = 700 g/ 1 gal

Therefore, the mass of fuel in 1 gallon = 700 g

The driver has 5.0 gallons of fuel in the tank.

The mass of 5.0 gallons of fuel = 5 × 700 = 3500 g of fuel

Equation of the combustion of fuel, C₅H₁₂ is given below:

C₅H₁₂ + 8 O₂ ---> 6 H₂O + 5 CO₂

1 mole C₅H₁₂ requires 8 moles of O₂

1 mole of C₅H₁₂ has a mass = 72 g

8 moles of O₂ has a mass = 256 g

Therefore, 300 g of O₂ will require 300 × (72/256) g of C₅H₁₂ = 84.375 g of C₅H₁₂

84.375 g of fuel is used by the car per lap;

20 laps will require 20 × 84.375 g of fuel = 1687.5 g of fuel.

Since there are 3500 g of fuel left in the tank, and he needs only 1687.5 g to complete 20 laps, he has enough fuel to complete the race. I will tell the driver that he does not need to make another pit stop as he has enough fuel to complete the race.

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