Answer:
P(O₂) = 287.41 mmHg
P(O₂) = 413.59 mmHg
Explanation:
Given data:
Total pressure = 701 mmHg
Mass of methane = 2.75 g
Mass of oxygen = 3.45 g
Partial pressure of each gas = ?
Solution:
Number of moles of methane:
Number of moles = mass/molar mass
Number of moles = 2.75 g/ 16 g/mol
Number of moles = 0.17 mol
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 3.45 g/ 32 g/mol
Number of moles = 0.12 mol
Total number of moles = 0.12 mol + 0.17 mol = 0.29 mol
Partial pressure of oxygen:
P(O₂) = [ moles of oxygen / total moles ] × total pressure
P(O₂) = [0.12 / 0.29 ] × 701 mmHg
P(O₂) = 0.41 × 701 mmHg
P(O₂) = 287.41 mmHg
Partial pressure of methane:
P(O₂) = [ moles of oxygen / total moles ] × total pressure
P(O₂) = [0.17 / 0.29 ] × 701 mmHg
P(O₂) = 0.59 × 701 mmHg
P(O₂) = 413.59 mmHg
