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slega [8]
3 years ago
6

Renaldo will write 3/20 as a decimal. Which of the following methods should he use?

Mathematics
2 answers:
BaLLatris [955]3 years ago
4 0

Answer:

1. Multiply the fraction by 5/5 to get a denominator of 100 and then write the numerator as hundredths using a decimal point.

Step-by-step explanation:

Renaldo must use a method that does not alter the value of the original fraction. This means that by multiplying the fraction by a number, the result obtained remains the same as the initial number.

Then the fraction \frac{3}{20} must be multiplied by the same number in the denominator and the numerator. For example:

\frac{3}{20}*\frac{5}{5}

\frac{3}{20}*\frac{33}{33}

If we multiply \frac{3}{20}*\frac{5}{5} the result is:

\frac{15}{100} To write this fraction in decimal form, we move the comma 2 digits to the left in the following way:

15.0 --------> 0.15.

Then \frac{15}{100}=\frac{3}{20}=0,15

The answer is Option 1.

makvit [3.9K]3 years ago
3 0

ANSWER

1. Multiply the fraction by 5/5 to get a denominator of 100 and then write the numerator as hundredths using a decimal point.

EXPLANATION

Renaldo wants to write

\frac{3}{20}

as a decimal.

He needs a denominator of 100, so he can multiply by

\frac{5}{5}

to obtain:

\frac{3}{20}  =  \frac{3 \times 5}{20 \times 5}

This will be

=  \frac{15}{100}

He can now obtain the decimal equivalent as

= 0.15

The correct choice is option 1.

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Simplify -7x - (15y) + 3x - 2y
LUCKY_DIMON [66]

Answer:

Step-by-step explanation:

combine like terms

-7x + 3x - 15y - 2y

-4x - 17y

3 0
3 years ago
The delivery ramp at the corner cafe id a right triangle. The hypotenuse is 4 meters long. One leg is 3 meters long. What is the
disa [49]

Answer:

f. sqrt 7 meters

Step-by-step explanation:

we use Pythagoras' theorem here,

let the unknown side be x,

therefore,

=> 3² + x² = 4²

=> x² = 16 - 9

=> x = √7 m

7 0
4 years ago
Read 2 more answers
For the function defined by f(t)=2-t, 0≤t<1, sketch 3 periods and find:
Oksi-84 [34.3K]
The half-range sine series is the expansion for f(t) with the assumption that f(t) is considered to be an odd function over its full range, -1. So for (a), you're essentially finding the full range expansion of the function

f(t)=\begin{cases}2-t&\text{for }0\le t

with period 2 so that f(t)=f(t+2n) for |t| and integers n.

Now, since f(t) is odd, there is no cosine series (you find the cosine series coefficients would vanish), leaving you with

f(t)=\displaystyle\sum_{n\ge1}b_n\sin\frac{n\pi t}L

where

b_n=\displaystyle\frac2L\int_0^Lf(t)\sin\frac{n\pi t}L\,\mathrm dt

In this case, L=1, so

b_n=\displaystyle2\int_0^1(2-t)\sin n\pi t\,\mathrm dt
b_n=\dfrac4{n\pi}-\dfrac{2\cos n\pi}{n\pi}-\dfrac{2\sin n\pi}{n^2\pi^2}
b_n=\dfrac{4-2(-1)^n}{n\pi}

The half-range sine series expansion for f(t) is then

f(t)\sim\displaystyle\sum_{n\ge1}\frac{4-2(-1)^n}{n\pi}\sin n\pi t

which can be further simplified by considering the even/odd cases of n, but there's no need for that here.

The half-range cosine series is computed similarly, this time assuming f(t) is even/symmetric across its full range. In other words, you are finding the full range series expansion for

f(t)=\begin{cases}2-t&\text{for }0\le t

Now the sine series expansion vanishes, leaving you with

f(t)\sim\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi t}L

where

a_n=\displaystyle\frac2L\int_0^Lf(t)\cos\frac{n\pi t}L\,\mathrm dt

for n\ge0. Again, L=1. You should find that

a_0=\displaystyle2\int_0^1(2-t)\,\mathrm dt=3

a_n=\displaystyle2\int_0^1(2-t)\cos n\pi t\,\mathrm dt
a_n=\dfrac2{n^2\pi^2}-\dfrac{2\cos n\pi}{n^2\pi^2}+\dfrac{2\sin n\pi}{n\pi}
a_n=\dfrac{2-2(-1)^n}{n^2\pi^2}

Here, splitting into even/odd cases actually reduces this further. Notice that when n is even, the expression above simplifies to

a_{n=2k}=\dfrac{2-2(-1)^{2k}}{(2k)^2\pi^2}=0

while for odd n, you have

a_{n=2k-1}=\dfrac{2-2(-1)^{2k-1}}{(2k-1)^2\pi^2}=\dfrac4{(2k-1)^2\pi^2}

So the half-range cosine series expansion would be

f(t)\sim\dfrac32+\displaystyle\sum_{n\ge1}a_n\cos n\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}a_{2k-1}\cos(2k-1)\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}\frac4{(2k-1)^2\pi^2}\cos(2k-1)\pi t

Attached are plots of the first few terms of each series overlaid onto plots of f(t). In the half-range sine series (right), I use n=10 terms, and in the half-range cosine series (left), I use k=2 or n=2(2)-1=3 terms. (It's a bit more difficult to distinguish f(t) from the latter because the cosine series converges so much faster.)

5 0
4 years ago
Clare has a recipe for yellow cake. She uses 913 cups of flour to make 4 cakes. Noah will follow the same recipe. He will make c
sergejj [24]

Answer:

(C)c= \frac{3}{7}f

Step-by-step explanation:

Clare uses 9\frac{1}{3} cups of flour to make 4 cakes.

It means  she uses 1 cup of flour to make 4\div9\frac{1}{3} cakes.

Let us simplify that expression first for future use.

4\div9\frac{1}{3}=4\div\frac{28}{3} =4 X \frac{3}{28} =\frac{3}{7}

Therefore, Clare uses 1 cup of flour to make \frac{3}{7} cakes.

If Noah follows the same recipe,

He uses f cups of flour to make c cakes

Using Ratio Method

→  Name  :  Cup  :  Cake

→  Clare   :    1        :   \frac{3}{7}

→  Noah   :     f       :   c

By using cross multiplication

c X 1 = \frac{3}{7}f

c= \frac{3}{7}f

The equation c= \frac{3}{7}f represents the relationship between c and f

8 0
4 years ago
Write out the following proportions in words. a. 7 :28 = 2 : 8 b. 3⁄1 = 18⁄6 c. 9 : 72 = 2 : 16 d. 81⁄9 = 45⁄5
Lerok [7]
1) Proportion a.

7 : 28 = 2 : 8

That means that the ratio 7 / 28 is equal to the ratio 2 : 8. 

You can verify the equality by simplifying to the simplest form:

     7 : 28 = 1 / 4 simplest form
     2 : 8 = 1 / 4 simplest form, then the proportion is right.

In words that is 7 is to 28 as 1 is to 4 ← answer


2) Proportion b.<span>. 3⁄1 = 18⁄6
</span><span>
</span><span>
</span><span>In words: 3 is to q as 18 is to 6 ← answer
</span><span>
</span><span>
</span><span>You can verify the proportion by simplifiying the second fraction:
</span><span>
</span><span>
</span><span>     18 / 6 = [18 / 6] / [ 6 / 6] = 3 / 1
</span><span>
</span><span>
</span><span>3) Proportion c. 9 : 72 = 2 : 16
</span><span>
</span><span>
</span><span>In words: 9 is to 72 as 2 is to 16 ← answer
</span><span>
</span><span>
</span><span>Proove the proportion:
</span><span>
</span><span>
</span><span>     9 / 72 = 1 / 8
</span><span>
</span><span>
</span><span>     2 / 16 = 1 / 8
</span><span>
</span><span>
</span><span>4) Proportion d. 81⁄9 = 45⁄5</span>

In words: 81 is to 9 as 45 is to 5 ← answer


Proove it: 
      81 / 9 = 9
      45 / 9 = 9
8 0
3 years ago
Read 2 more answers
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