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baherus [9]
4 years ago
13

Find the zeros of polynomial function and solve polynomials equations. f(x)=81x^4-16

Mathematics
1 answer:
sleet_krkn [62]4 years ago
5 0

After factoring you get the equation:

(3x-2)(3x+2)(9x^{2}+4)

Your real zeros are -2,2

How do you mean "solve polynomial equations?"

Which polynomials?

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What does 2 10/19 plus 3 9/12 equal? ​
Dennis_Churaev [7]
It equals 6 21/79 aaaaaaa
7 0
3 years ago
F(x)= 2lxl? (graphing absolute values) I'm a little confused.
Vesnalui [34]
I see. Imagine you have f(x)=|x|. It's a V shaped graph.

Now if f(x)=|x|, 2f(x)=2|x|.

Graph Transformation Rule:

af(x), multiply y-coordinates by a.

*Ultimately, you'd still have a V shaped graph in 2f(x)=2|x|, but the y values of all the coordinates in f(x)=|x| would have to be multiplied by 2 giving you 2f(x)=2|x|.
6 0
4 years ago
Read 2 more answers
Given the function fx=x^2-4x-5 identify the zeros using factorization
Mnenie [13.5K]

Answer:

x = 5,-1

Step-by-step explanation:

(x-5)(x+1)

7 0
3 years ago
Answer all the questions:
nata0808 [166]

Answer:

Step-by-step explanation:

nmndndacanadakdndjqnjqenedjqdnqednaansndwenfqwndca

4 0
4 years ago
Add in the indicated base. 333 (sub)5 + 30 (sub)5
Vladimir [108]
In base 5 the place values (from right to left) are the ones place, the 5's place and the 25's place.  The highest digit you can write in any column is a 4.   

333 would be (3 x 25) + (3 x 5) + (3 x 1) which is 93 in base 10.
30 would be (3x5) + (0 x 1)  which is 15 in base 10.
The sum of 93 and 15 is 108 in base 10.
Now lets write that in base 5 -    We can have 4 25's so there will be a 4 in the 25's column.  Since 4 x 25 = 100 we still have to account for 8 to get to 108.
We can have 1 five  in the 5's columns since 1 x 5 is 5.  Now we have 3 left over which we can place in the one's column
Final answer 333₅ + 30₅ = 413₅
5 0
3 years ago
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