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vichka [17]
3 years ago
13

The high temperature on friday was 8 degrees above zero

Mathematics
1 answer:
pshichka [43]3 years ago
6 0
0-8=-8
the answer is -8
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Use the position function s(t) = –4.9t2 + 500, which gives the height (in meters) of an object that has fallen for t seconds fro
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Complete Question

The complete question is shown on the first uploaded image

Answer:

The  value is  v(3) =  29.4 \  m/s

Step-by-step explanation:

From the question we are told that

    s(t) =  -4.9t^2 + 500

And  

    \lim_{t \to a}  \frac{s(a) - s(t)}{a-t}

Generally s(t) at t = a is mathematically evaluated as

      s(a) =  -4.9a^2+ 500

So

    s(a) - s(t) =  -4.9a^2 + 500 - ( -4.9t^2+500)

     s(a) - s(t) =  -4.9a^2 + 500 +4.9t^2-500)

      s(a) - s(t) = 4.9(t^2 - a^2)

Thus the velocity is represented as

     v(t) =\lim_{t \to a}  \frac{s(a) - s(t)}{a-t} \equiv \lim_{t \to a} \frac{4.9(t^2 -  a^2 )}{ a-t}

=>     v(t) = \lim_{t \to a}  - 4.9(a + t )

=>      v(t) = -4.9 (a + a )

=>      v(t) = -9.8a

Now at  t =  3

=>  v(3) = -9.8 (3)

=>   v(3) =  29.4 \  m/s

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Step-by-step explanation:

I used omnicalculator. Should count because it's still a calculator.

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