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raketka [301]
4 years ago
12

Jason is working on a project that requires him to manage a huge amount of data. The spreadsheet he is working on has data relat

ed to the
official budget from cell A1 through C9, and data related to actual expenditures from cell L1 through N19. How will Jason track and compare the
data as he works on the spreadsheet?
Computers and Technology
1 answer:
Delicious77 [7]4 years ago
8 0

Answer:

By using various tools.

Explanation:

<em>You can compare excel files and data using different tools which are available online and even in your local files. Listed below are the ways and procedure for you to compare data in excel: </em>

<em>1. By using Microsoft Word  </em>

<em>Procedure :  </em>

<em>1.1 Select cells with the data that you want to compare. Copy them or simply press Ctrl key and C key and paste in on a blank word document. Remember to select only the data that you need to compare not the whole worksheet at it may cause the document to load slower. </em>

<em>1.2 You should have two files. Old.doc which contains the old documents and New.doc which contains the changes that you have made on the previous document. </em>

<em>1.3 Using Microsoft Word, Go to Tools, then Track Changes then select Compare documents. </em>

<em>1.4 You can now view the changes from the old to new document </em>

<em>2. Using Microsoft Excel itself </em>

<em>Procedure: </em>

<em>2.1 Paste the old texts and contents in Cell A1. </em>

<em>2.2 Paste the new texts and contents in Cell B1. </em>

<em>2.3 In Cell C1, use the formula =IF(A1=B1,"","!") </em>

<em>2.4 Double click on the ,,+" when t shows in cell C1 </em>

<em>2.5 You can now see the two different versions of the texts. </em>

<em>3. You can use online tools which are available via search engines. </em>

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Write a Python function that will accept as input three string values from a user. The method will return to the user a concaten
Aleks04 [339]

Answer:

Following are the program in python language

def cat_rev(x,y,z): # function definition  

   x=x[::-1]# reverse the first string  

   y=y[::-1]# reverse the second string  

   z=z[::-1]# reverse the third string  

   z=x+y+z;  #concat the string

   return(z)#return the string

   #main method

s=input("Enter the first string:") #read the first string

r=input("Enter the second string:")#Read the second string  

t=input("Enter the third string:")#Read the third string by user

rev1= cat_rev(s,r ,t ) #function calling

print(rev1)# display reverse string

Output:

Enter the first string:san

Enter the second string:ran

Enter the third string:tan

nasnarnat

Explanation:

Following are the description of program

  • In the main function we read the three value by the user in the "s", "r" and "t" variable respectively.
  • After that call the function cat_rev() by pass the variable s,r and t variable in that function .
  • Control moves to the function definition of the cat_rev() function .In this function we reverse the string one by one and concat the string by using + operator .
  • Finally in the main function we print the reverse of the concat string   .

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3 years ago
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Write a python computer program that prints out a factorial.
galina1969 [7]

I included my code in the picture below.

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While reviewing some web page code, you notice that the html is written in all lowercase letters. you are not sure which version
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3 years ago
We have said that the average number of comparisons need to find a target value in an n-element list using sequential search is
bija089 [108]

Answer:

Part a: If the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b: If the list contains n elements (where n is even) the middle terms are  at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c: The average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

Explanation:

Suppose the list is such that the starting index is 0.

Part a

If list has 15 elements, the middle item would be given at 7th index i.e.

there are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(8,9,10,11,12,13,14) above it. It will have to run 8 comparisons  to find the middle term.

If list has 17 elements, the middle item would be given at 8th index i.e.

there are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(9,10,11,12,13,14,15,16) above it.It will have to run 9 comparisons  to find the middle term.

If list has 21 elements, the middle item would be given at 10th index i.e.

there are 10 indices (0,1,2,3,4,5,6,7,8,9) below it and 10 indices (11,12,13,14,15,16,17,18,19,20) above it.It will have to run 11 comparisons  to find the middle term.

Now this indicates that if the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b

If list has 16 elements, there are two middle terms as  one at would be at 7th index and the one at 8th index .There are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(9,10,11,12,13,14,15) above it. It will have to run 9 comparisons  to find the middle terms.

If list has 18 elements, there are two middle terms as  one at would be at 8th index and the one at 9th index .There are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(10,11,12,13,14,15,16,17) above it. It will have to run 10 comparisons  to find the middle terms.

If list has 20 elements, there are two middle terms as  one at would be at 9th index and the one at 10th index .There are 9 indices(0,1,2,3,4,5,6,7,8) below it and 9 indices(11,12,13,14,15,16,17,18,19) above it. It will have to run 11 comparisons  to find the middle terms.

Now this indicates that if the list contains n elements (where n is even) the middle terms are  at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c

So the average number of comparisons is given as

((n+1)/2+(n+2)/2)/2=(2n+3)/4

So the average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

6 0
3 years ago
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