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QveST [7]
3 years ago
13

I need help with this question!!!

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0
Its the first one I believe: 5/2 and 25/4
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Our answer should be a complex number in the form a +bi where a and b are real numbers.
Otrada [13]

Answer:

16 +88i

Step-by-step explanation:

8 x (11i + 2 ) =

Distribute

8*11i + 8*2

88i +16

Writing in the proper form

16 +88i

6 0
3 years ago
How do you multiply fractions with a whole number
Allisa [31]
You put the whole number on top of 1, it doesnt change its value. then you simplify across like in a butterfly only if needed then you multiply across from left to right.

5 0
3 years ago
Read 2 more answers
The senior classes at High School A and High School B planned separate trips to Lake Compounce. The senior class at High School
storchak [24]

Answer:

Number of students in vans =15 and bus =46

Step-by-step explanation:

use variables for the vans and buses

let x= vans and y=buses

Now solve the 2 equations simultaneously

<em><u>remember</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>your</u></em><em><u> </u></em><em><u>equations</u></em>

6x+7y=412..........1

6x+9y=504.........2

make x the subject of one equation

and label it equation 3

6x=412—7y

x =  \frac{206}{3}  -  \frac{7y}{6} .............3

subs 3 into 2

6( \frac{206}{3}  -  \frac{7y}{6} ) + 9y = 504

412 - 7y + 9y = 504

- 7y + 9y = 504 - 412

2y = 92

y = 46...................4

subs 4 into 1

6x + 7(46) = 412

6x + 322 = 412

6x = 412 - 322

6x = 90

x = 15

Therefore there are 15 students in each van and 46 students in each bus.

3 0
3 years ago
A museum requires a minimum number of chaperones proportional to the number of students on a field trip. The museum requires a m
Stells [14]

Answer: See explanation

Step-by-step explanation:

Here is the complete question:

A museum requires a minimum number of chaperones proportional to the number of students on a field trip. The museum requires a minimum of 3 chaperones for a field trip with 24 students. Which of the following could be combinations of values for the students and the minimum number of chaperones the museum requires? Choose 2 answers.

A. Students: 72

Minimum of chaperones: 9

B. Students: 16

Minimum of chaperones: 2

C. Students: 60

Minimum of chaperones: 6

D. Students: 45

Minimum of chaperones: 5

E. Students: 40

Minimum of chaperones: 8

Since the museum requires a minimum of 3 chaperones for a field trip with 24 students. This means that there will be 24/3 = 8 students per chaperone.

We then divide the number of students given in the question by the number of chaperone to know our answers. This. Will be:

Students: 72

Minimum of chaperones: 9

This will be: 72/9 = 8

Therefore, this is correct.

B. Students: 16

Minimum of chaperones: 2

This will be: 16/2 = 8

This is correct

C. Students: 60

Minimum of chaperones: 6

This will be: = 60/6 = 10.

Therefore, this is wrong

D. Students: 45

Minimum of chaperones: 5

This will be 45/5 = 9

Therefore, this is wrong.

E. Students: 40

Minimum of chaperones: 8

This will be: 40/5 = 8.

Therefore, this is wrong.

Therefore, options A and B are correct.

3 0
3 years ago
Read 2 more answers
Please no links or files
Nana76 [90]

Answer:

A

Step-by-step explanation:

2.25 > 1 5/6 > 1/2 > -1.5 > -3 1/4

6 0
2 years ago
Read 2 more answers
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