Find 3 consecutive even integers such that the sum of twice the smallest number and 3 times the largest is 42
1 answer:
integers n, n+2 , n+4
2n + 3(n+4) = 42
2n + 3n +12 = 43
5n +12 = 42
5n = 30
n = 6
integers 6, 8 ,10
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