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statuscvo [17]
3 years ago
9

The function f(x) = 2(3)x represents the growth of a dragonfly population every year in a remote swamp. Rose wants to manipulate

the formula to an equivalent form that calculates seven times a year, not just once a year. Which function is correct for Rose's purpose, and what is the new growth rate? f(x) = 2(3)x; growth rate 200% f(x) = 2(1.17)7x; growth rate 17% f(x) = 2(3)x, growth rate 2% f(x) = 2(1.17)x; growth rate 2%
Mathematics
2 answers:
tia_tia [17]3 years ago
7 0

Answer : option B

The function f(x)= 2(3)^x represents the growth of a dragonfly population every year.

Rose wants to manipulate the formula to an equivalent form that calculates seven times a year, not just once a year. So function becomes

f(x)= 2(3^\frac{1}{7})^{7x}

In exponential function , f(x) = a(1+r)^x, where 'r' is the growth rate

f(x)= 2(1.17)^{7x}

1 + r = 1.17

r = 0.17

So growth rate = 0.17= 17%

f(x)= 2(1.17)^{7x} ; growth rate 17%

stiks02 [169]3 years ago
3 0
I might be wrong but i think it’s the second one
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Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

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34=\left [ (x-4)^2+(y-1)^2 \right ]+\left [ (x+1)^2+(y+2)^2 \right ]

Put (x,y)=(-1,1)

34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34

which is true. So, (-1,1) can be a vertex

Put (x,y)=(4,-2)

34=\left [ (4-4)^2+(-2-1)^2 \right ]+\left [ (4+1)^2+(-2+2)^2 \right ]\\34=9+25\\34=34

which is true. So, (4,-2) can be a vertex

Put (x,y)=(1,1)

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Put (x,y)=(2,-2)

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which is not true. So, (2,-2) cannot be a vertex

Put (x,y)=(4,-1)

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which is not true. So, (4,-1) cannot be a vertex

Put (x,y)=(-1,4)

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