Question

Solve the quadratic equation using any method. Round to the nearest tenth if neccessary. Any Help Is Appreciated

Answer 1

Answer:

$x = -0.8\ or\ x = 0.5$

Step-by-step explanation:

Given [Missing from the question]

$6x^2 + 2x - 2.5 = 0$

Required

Solve

Using factorization, we have:

$6x^2 + 2x - 2.5 = 0$

Expand 2x

$6x^2 - 3x+5x - 2.5 = 0$

Factorize

$3x(2x - 1)+2.5(2x - 1) = 0$

Factor out 2x - 1

$(3x +2.5)(2x - 1) = 0$

Split:

$(3x +2.5) = 0\ or\ (2x - 1) = 0$

In both cases, solve for x

$3x = -2.5\ or\ 2x = 1$

$x = -\frac{2.5}{3}\ or\ x = \frac{1}{2}$

$x = -0.8\ or\ x = 0.5$ --- approximated