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STALIN [3.7K]
3 years ago
10

How is 6.35 x 10^11 written in standard form

Mathematics
1 answer:
liberstina [14]3 years ago
8 0
6.35*10^{11}.
To do this, we move the decimal point 11 spaces to the right.
So, our answer is :
635000000000
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Which of the following are solutions to the equation below?
Luden [163]

Answer:

c) -4/5

d) 4/5

Step-by-step explanation:

The given equation is 25x^2 -16 = 0

Adding 16 on both sides, we get

25x^2 = 16

Dividing both sides by 25, we get

x^2 = 16/25

Taking square root on both sides, we get

x = √(16/25)

x = ±4/5

Therefore, x = 4/5 and x = -4/5

Answers: C) and D)

Hope this will helpful to understand the concept.

Thank you.

4 0
3 years ago
Use an area model to solve. 1 3/4 X 2 1/2
Sauron [17]
I can give you the answer right of the top of my head here it is 1 and 3/4 x 2 and 1/2 is 4 and 3/8
4 0
3 years ago
One hundred 50 cent coins have a mass of 690g. What is the mass of one 50 cent coin?
olga nikolaevna [1]
You divide 690 by 100 which is 6.9
Therefore, one 50cent coin is 6.9g
7 0
3 years ago
Read 2 more answers
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
3 years ago
What is the value of expression MATH HELP
iris [78.8K]
All of the answer choices that you are given are incorrect. I have calculated it in all different ways and get the same thing and it is none of those. The correct answer would be -75 though.
7 0
3 years ago
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