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STALIN [3.7K]
3 years ago
10

How is 6.35 x 10^11 written in standard form

Mathematics
1 answer:
liberstina [14]3 years ago
8 0
6.35*10^{11}.
To do this, we move the decimal point 11 spaces to the right.
So, our answer is :
635000000000
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Use the formula for a cylinder r=4 h=8 v?
zzz [600]

Answer:

\large\boxed{V=128\pi\approx401.92}

Step-by-step explanation:

The formula of a volume of a cylinder:

V=\pi r^2h

We have r = 4 and h = 8:

V=\pi(4^2)(8)=\pi(16)(8)=128\pi

\pi\approx3.14\to V\approx(128)(3.14)=401.92

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How do u do parabola
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Step-by-step explanation:

Finding the vertex or the end of the shape.

Find the y -intercept, (0,f(0)) ( 0 , f ( 0 ) ) .

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3 years ago
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Samantha can make 48 pizza’s in an 8 hour work day.
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3 years ago
Let f(x)=241+3e−1.3x . What is the point of maximum growth rate for the logistic function f(x) ? Round your answer to the neares
FromTheMoon [43]

Answer:

The point of maximum growth is at x=0.82

Step-by-step explanation:

Given a logistic function

f(x)=\frac{24}{1+e^{-1.3x}}

we have to find the point of maximum growth rate for the logistic function f(x).

From the graph we can see that the carrying capacity or the maximum value of logistic function f(x) is 24 and the point of maximum growth is at y=\frac{24}{2} i.e between 0 to 12

So, we can take y=\frac{24}{2} and then solve for x.

\frac{24}{2}=\frac{24}{1+e^{-1.3x}}

⇒ 2=1+3\exp{-1.3x}

⇒ 1=3.\exp{-1.3x} ⇒ \frac{1}{3}=\exp{-1.3x}

                             ⇒ log 3=-1.3x

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Hence, the point of maximum growth is at x=0.82


5 0
3 years ago
Find the volume of a pyramid with a square base, where the perimeter of the base is 13.4 in and the height of the pyramid is 7.6
VashaNatasha [74]

Answer:

28.4in³

Step-by-step explanation:

Volume of the square based pyramid = L²H/3 where;

L is the length of a side of the square base

H is the height of the prism

Given

Perimeter of the base = 13.4 in

Height of the pyramid = 7.6in

First we need to get the length of the square base

Perimeter of a square = 4L

13.4 = 4L

L = 13.4/4

L = 3.35 in

Next is to find the required volume of the pyramid

V = L²H/3

V =  3.35²(7.6)/3

V = 85.291/3

V =  28.4 in³

Hence the volume of the pyramid to nearest tenth is 28.4in³

7 0
3 years ago
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