Ask question

Ask question

All categories

2 years ago

5

You are presented with a deck of 10 cards, numbered from 1 to 10 and can draw one card. If the number is odd, you win $14. If th

e number is even, you win nothing. If you play the game, what is the expected pay off?
$__

1 answer:

Alexus [3.1K]2 years ago

5 0

I believe it will be 14 I am not sure

You might be interested in

What are three ways to write the number 24? Please help!!!!!!

Diano4ka-milaya [45]

24, 12x2, 6x4, and 48/2

6 0

2 years ago

15+6=33m-21-27m<br><br> combining like terms (show work)

marin [14]

Answer:

$m = \boxed 7$

Combine like terms

$21=33\cdot \mathrm{m}-21-27\cdot \mathrm{m}$

Group like terms

$21=\left(33\cdot \mathrm{m}-27\cdot \mathrm{m}\right)-21$

Simplify the arithmetic

$21=6\cdot \mathrm{m}-21$

Swap sides

$6\mathrm{m}-21=21$

7 0

1 year ago

natita [175]

Answer:

the answer is -1. please thank my answer please and thank you

3 0

3 years ago

If there were 300 accidents in 1967 and 380 in 1968, what is the percent increase?

VikaD [51]

First find the amount of increase: 380-300=80. Then divide the amount of increase by the original amount: 80/300=.266666667. Normally you round to the tenths place: .27. Then make it a percent: .27=27%. The percent of increase is 27% :) hope this helps

3 0

2 years ago

Read 2 more answers

Can someone please be amazing and help me solve number 2?

inessss [21]

The answer is

T2=(P2V2/T1)/P1V1

7 0

2 years ago