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katovenus [111]
3 years ago
12

The slope of the line below is 2 use the coordinates of the labeled point to find a point slope equation of the line

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
8 0

Answer:

B. y-10=2(x-3)

Step-by-step explanation:

Apex

Hope this helps Have a nice day

yan [13]3 years ago
5 0

Answer:

B.

Step-by-step explanation:

The answer is B. The problem says that the slope is 2 and it as the points (3,10) on its line. When looking at the graph, you can see that the line crosses at four on the y-intercept which is why four will be your constant. So, your equation in slope intercept form will become y=2x+4. With this, you can start eliminating the given answers.

You can immediately eliminate c and d because the 2 is negative when it isn't in its slope form. It leaves you with a and b.

When looking at both a and b you now have to look at what your y will become when you sinplify both of them. In choice a, the 2 multiplies with the 3 and gives you 6. Since you have to leave the y by itself you have to subtract 10 from both sides which will leave you with -4. Since your y-intercept isn't negative you know that a isnt the ansewr.

When checking b, you multiply the 2 and -3 to get -6. Since you have to leave the y by itself, you add 10 to each side and end up with 4 which is the same number that crosses the y-axis. and that is how you know it's the right answer.

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KIM [24]

Answer:

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Step-by-step explanation:

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3 0
2 years ago
In which case would it be necessary to find the area of this circle
9966 [12]
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3 years ago
a box holds red pens and blue pens the ratio of red pens to blue pens is 1 to 4 The box holds 12 more blue pens than red pens wh
Genrish500 [490]

Answer:

20 pens

Step-by-step explanation:

if there is 1 red pen for every 4 blue pens

then

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nignag [31]
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6 0
3 years ago
The diagonals of rhombus ABCD intersect at E. Given that m∠CAD=20° and CE=4, find the m∠CDA.
morpeh [17]

Given :

The diagonals of rhombus ABCD intersect at E.

∠CAD = 20°.

To Find :

The angle ∠CDA.

Solution :

We know, diagonals of a rhombus bisects each other perpendicularly.

So, ∠DEA = 90°.

In triangle ΔEAD :

∠EAD + ∠AED + ∠EDA = 180°

20° + 90° + ∠EDA = 180°

∠EDA = 70°

Now, we know diagonal of rhombus also bisect the angle between two sides .

So, ∠CDA = 2∠EDA

∠CDA = 2×70°

∠CDA =140°

Therefore, ∠CDA is 140°.

3 0
3 years ago
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