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tankabanditka [31]
3 years ago
7

How do I find the surface area of a a triangular prisim

Mathematics
2 answers:
Marrrta [24]3 years ago
4 0
Area = base x heights so you multiply all the sides together. 
Mrac [35]3 years ago
4 0
Top and Bottom Surface = 2(Length x Width)

4 Lateral Surface = 2(Length + Width) x Height

So, Surface area = 2(Length x Width) + 2(Length + Width) x Height
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What is the distance between (4, 3) and (7, 3)?
Damm [24]

Answer:

3 units

Step-by-step explanation:

5 0
2 years ago
How do you find the slope intercept form for a slope that is -2 passing through points (4,-3)
Veseljchak [2.6K]
To find the slope intercept form, you plug in the slope and the points given and find whats missing
y=mx+b
slope is -2 
given points are (4,-3)

-3=-2(4)+b  (multiply -2 and 4)
-3=-8+b  (add 8 to both sides)
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so the equation for the slope intercept form would be
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8 0
3 years ago
Eight hundred thirty-three billion, four hundred thousand,<br> nine hundred six
kompoz [17]

Answer:

What's the question?

Step-by-step explanation:

I will help if I knew the question

7 0
2 years ago
Question 5 (12 points)
Dima020 [189]

Answer:

see attached for diagram

a) √13

b) √29

c) 4

Step-by-step explanation:

Equation of the circle:  (x + 1)^2 + (y - 3)^2 = 16

⇒ center = (-1, 3)

⇒ radius = √16 = 4

Distance between 2 points formula:

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

a)  let (-1, 3) = (x_1,y_1)

    let (2, 1) = (x_2, y_2)

 \implies \sqrt{(2+1)^2+(1-3)^2} =\sqrt{13}

b)  let (-1, 3) = (x_1,y_1)

    let (4, 1) = (x_2, y_2)

\implies \sqrt{(4+1)^2+(1-3)^2} =\sqrt{29}

c)  let (-1, 3) = (x_1,y_1)

    let (3, 3) = (x_2, y_2)

\implies \sqrt{(3+1)^2+(3-3)^2} =4

4 0
2 years ago
Read 2 more answers
Which equation matches the grpah? A.y = - 1/2x B.y = 1/2x C. y = 2x D. y = -2x
My name is Ann [436]

Answer: it is c all u have to do seach up desmos in put in the graph promblem is will show u the answer

Step-by-step explanation:

3 0
3 years ago
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