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Sophie [7]
2 years ago
5

I recently took a test in my Algebra 1 class. This was on the test (that I most likely failed)and it said something about vertic

al motion. The problem is below. Try to solve it, please! Thanks!
2=-t^2+4+5
Mathematics
1 answer:
luda_lava [24]2 years ago
5 0

OK.                                         <u>2 = -t² + 4t + 5</u>

Subtract 2 from each side:     0 = -t² + 4t + 3

Multiply the right side by  -1 :  0 = t² - 4t - 3

Unfortunately, this can't be factored.  The only other way I know
to find the solutions to a quadratic equation is with the use of the
quadratic formula.  When you do that, you get these solutions:

     t = 2 + √7 = about<em>  4.65</em>
and
     t = 2 - √7 = about  <em>-0.65</em> .

If this equation comes from a problem that involves real people throwing
real things into the air and making vertical motion, then you want only the
positive solution.


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3 years ago
A bag contains purple marbles and blue marbles, 41 in total. The number of purple marbles is 4 less than 2 times the number of b
Andreas93 [3]

Answer:

There are 26 purple marbles in the bag.

Step-by-step explanation:

1) We have purple (p) and blue (b) marbles in a bag, and 41 marbles total so:

p+b = 41

2) we want to know how many purple marbles we have, so let's rearrange for p:

p = 41 - b

3) Our problem gives us an expression for the purple marbles in terms of the blue,  let's write it using math symbols instead of words:

<em>"The number of purple marbles is 4 less than 2 times the number of blue marbles."</em>

so: p = 2b - 4

3) Now we're going to plug this in (or substitute it) for our p in our first equation, and solve for b

p = 41 - b

2b - 4 = 41 - b     (substitution)

2b = 45 - b         ( add 4 to both sides)

3b = 45               (add b to both sides)

b = 15                  (divide both sides by 3)

4, last step!)

Now we know we have 15 blue marbles, that's great! But we still want to know how many purple marbles we have.

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4 0
3 years ago
Simplify the imaginary number sqr -75
m_a_m_a [10]

Answer:

5i\sqrt{3}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

and \sqrt{-1} = i

Given

\sqrt{-75}

= \sqrt{25(3)(-1)}

= \sqrt{25}  × \sqrt{3} × \sqrt{-1}

= 5 × \sqrt{3} × i

= 5i\sqrt{3}

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3 years ago
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Answer:

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