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3 years ago

How does this model demonstrate the Pythagorean Theorem?

1 answer:

3 0

<span>" B is your best choice but it is very badly stated. this gives an Example of the Pythagorean theorem. it does Not demonstrate it. B is written incorrectly, it should say "sum of squares of the lengths of the legs" Not "sum of the lengths of the two legs of any right angle squared"</span>

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Find 4.23 - 6.87 Write your answer as a decimal

patriot [66]

Answer:

-2.64

Step-by-step explanation:

3 0

3 years ago

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A new operation is defined by a△b=a^2-b/b-a^2. 4△3.

dmitriy555 [2]

As the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1

As per the question statement, we are given a new mathematical operation a△b=a^2-b/b-a^2 and we are supposed to find the value of 4△3 using the same operation.

Given, a△b=a^2-b/b-a^2

now 4△3 = (4^2-3) / (3-4^2)

4△3 = (16-3) / (3-16)

4△3 = 13 / -13

4△3 = -1

Hence, as the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1.

Mathematical operation: An operator in mathematics is often a mapping or function that transforms components of one space into elements of another.

To learn more about mathematical operation, click on the link given below:

brainly.com/question/8959976

#SPJ1

8 0

1 year ago

Which of the following is a radical equation

Luden [163]

Its b because yeah im just kidding idk im really stupid jk its b hahaha

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2 years ago

You have just opened a new nightclub, Russ' Techno Pitstop, but are unsure of how high to set the cover charge (entrance fee). O

Neko [114]

Answer:

a)q(p)=-15p+ +300

b)R(p)=-15p²+300p

c)C(p)=-30p+1600

d.1)P(p)=-15p²+330p-1600

d.2)p=$11

Step-by-step explanation:

(a).Before getting started, we are going to consider the cartesian plane, where x-axis corresponds to the cover charge and y-axis corresponds to number of guests per night . There, we will locate the following coordinates according to the previous information:

(9,165) (10,150).

Remember that the slope-intercept form of the linear equation is y=mx+b where m is the slope and b is te intercept.

The slope can be calculated by the next formula:

$m=\frac{y2-y1}{x2-x1}$

In this case we will assign (9,165) as the first coordinate and (10,150) as the second one. The order does not matter. At the end we get the same value for m.

Therefore:

$m=\frac{150-165}{10-9} = -15$

Now, we have the slope and two poitns. According to this, and taking into account that point-slope form of the equation of a line is y-y1=m(x-x1), find a linear demand equation.

Any of two coordintates can be selected. In this case we will select the second one.

y-150=-15(x-10) equation 1

Solve equation 1 for y

y=-15x+150+150

y=-15x+300

Above we had defined x as cover charge (p) and y as number of guests (q). Thus, rewrite equation 1.

q(p)=-15p+ +300.

it equation shows the number of guests per night as a function of the cover charge,

(b). The nightly revenue can be calculated multplying the price of the cover charge by the number of guests. So, we just have to multiply the equation 1 by p.

p*q(p)=p*(-15p +300)

R(p)=-15p²+300p equation 2

(c) To get the cost function of the nightclub we just have to multiply the cost of the two non-alcoholic drinks by the number of the guests ( equation 1) and add to it nightly overheads.

C(p)=2*(-15p+300)+1000

C(p)= -30p+600+1000

C(p)=-30p+1600 equation 3

(d) In order to find the profit in terms of the cover charge we will subtract nightly costs ( equation 3) from nightly revenue (equation 2)

P(p)=R(p)-C(p)

P(p)=-15p²+300p - (-30p+1600)

P(p)=-15p²+300p+30p-1600

P(p)=-15p²+330p-1600

To determine that the entrance fee we should charge for a maximum profit we are going to use the first derivative test (y'(x)=0) in order to find an extremum point.

Compute the first derivative of P(p)

P'(p)=-30p+330=0

30p=330

p=330/30

p= $11

The entrance fee that we should charge for a maximum profit is p=$11 per guest.

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3 years ago

John Stone rents a car. John has a fixed rate of $49.00 weekly, pays $14.00 per week for the optional insurance, and he spends $

charle [14.2K]

300 dollars per month

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3 years ago

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