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Dovator [93]
3 years ago
7

Which of the following is the main advantage of experiments?

Advanced Placement (AP)
1 answer:
Tcecarenko [31]3 years ago
5 0
They allow the researcher to generate many hypotheses.
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inessss [21]

Answer:

(b)

A dealer gains 16% by selling a mop for Rs 78,300. But, due to competition in the market, he decides to make a profit of only 10%. What is its new selling price?

Explanation:

(b)

A dealer gains 16% by selling a mop for Rs 78,300. But, due to competition in the market, he decides to make a profit of only 10%. What is its new selling price?(b)

A dealer gains 16% by selling a mop for Rs 78,300. But, due to competition in the market, he decides to make a profit of only 10%. What is its new selling price?

7 0
1 year ago
1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The
Arlecino [84]

Hi there!

a.

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt

Evaluate using a calculator:

= 899.97 \approx \boxed{900\text{ people}}

b.

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt

We can evaluate using a calculator (math-9 on T1-84):


\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt

= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}

c.

If:
P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt

Then:

\frac{dP}{dt}  = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt  = S(t) - R(t)

Evaluate at t = 20:


S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669

S(20) - R(20) = 87.844 - 108.669 = -20.823

This means that at t = 20, there is a <u>NET DECREASE</u> of people at the movie theater of around 20.823 (21) people per hour.

d.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

<u>Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.</u>

8 0
2 years ago
At this intersection, how should you proceed? A. Stop and wait for the red lights to stop flashing
n200080 [17]
The answer is b) respond to the flashing red lights as if they are a stop sign
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In the second and third sentences of the fifth paragraph (“He stops . . . gradual explanation”), the author presents a humorous
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Answer:

D. desire to surprise his friend and his friend’s failure to recognize him

Explanation:

Answer D

Correct. In these sentences, the author presents a humorous reversal that emerges from the ironic incongruity between the traveler’s plan to “overpower” his old friend with an excess of pleasure and the anticlimactic outcome of the surprise visit. As it turns out, the friend experiences no immediate pleasure from the visit because he fails to recognize the traveler and can only be made to remember him after the traveler gives a “gradual (in this context, methodical) explanation” of who he is.

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3 points of use of X-rays ??
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They are used as radio waves, infrared radiation, visible light.
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