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Effectus [21]
2 years ago
12

Approximately how much time did it take for the human population to initially double? (to go from 250 million to 500 million).

Advanced Placement (AP)
1 answer:
zhenek [66]2 years ago
4 0

Answer:

300 years

Explanation:

thats what i that is i think sorry if i'm wrong this is my first question

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Which sum is prime? A) 1 + 3 B) 2 + 4 C) 5 +8 D) 7+9
puteri [66]

Answer:

C

Explanation:

In other option ,the result comes out to be even

in option A, its 4

in option B,its 6

in option C,its 13

in option D,its 16

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3 years ago
Barney wants to rent a tent. He has to pay a fixed base cost plus a daily rate for renting the tent. The table shows the amount
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x) Rent (dollars)

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Which equation best shows the relationship between x and y?

y = 5x + 3

y = x + 8

y = 5x + 8How much more would the value of y be on the graph than its value in the table when x = 12?

20

30

60

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Question 7(Multiple Choice Worth 1 points)

(05.01 LC)

The graph below shows the height through which The values on the y-axis are from 0 to 125 in increments of 25 for each grid line. A line is shown connecting points on ordered pair 1, 25 and 2, 50 and 3, 75 and 4, 100. The title of the graph is Rate of Ascent.

What is the rate of change for the relationship represented in the graph?

50

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Explanation:

6 0
3 years ago
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6 different types of people as roadway users
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Answer:

1. pedestrians

2. cyclists

3. motorists

4.vehicle passengers

5. horse riders

6. passengers of on-road public transport

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3 years ago
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Limit as x approaches 0 of (2e^x-2)/x
Snowcat [4.5K]

Answer:

Explanation:

\lim_{x \to \ 0} \frac{2e^x-2}{x}

So first, we have to plug in zero and see if we can evaluate this limit simply from that.

When we plug in zero we get: (2e^0-2)/0

e^0 is 1 so we have 2-2/0 or 0/0. So we have an indeterminate form type 0/0.

This means we have to apply L'Hospital's Rule.

As a reminder L'Hospitals Rule is \lim_{x\to \ c} \frac{f'(x)}{g'(x)}

Meaning that we take the derivative of the top and bottom function as the approach some value "c". We can do this with a 0/0 indeterminate form.

So:

The derivative of 2e^x - 2 is just 2e^x

and the derivative of x is 1

So we are left with \lim_{x \to \ 0} 2e^x

Plugging in zero we see this gives us 2 as 2(e^0) = 2(1) = 2.

Hence, \lim_{x \to \ 0} \frac{2e^x-2}{x} = 2

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3 years ago
Which of the following health-related problems can best be solved by community action?
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Hey there

the Answer is

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