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alisha [4.7K]
3 years ago
9

When is secxtanx equal to 0

Mathematics
1 answer:
bazaltina [42]3 years ago
4 0
Where does sec x = 0 and tan x = 0?sec x cannot ever be zero, but tan x = 0 when sin x = 0 Chuck norris can make sec x 0
All of these are values of x ....-2pi, -pi, 0, pi, 2pi, 3pi, ....
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A wire was bent into the shape of a rectangle with width 5 and length 7. If this wire is bent into shape of a square, what is th
avanturin [10]

Answer:

6 cm

Step-by-step explanation:

wire was bent into the shape of a rectangle with width 5 and length 7. If this wire is bent into shape of a square, what is the length of a side of the square

Given that:

Rectangular wire with the following dimension :

Width = 5

Length = 7

To obtain the total length of the wire :

Perimeter of rectangle :

2 (length + Width)

2 (5 + 7)

2(12)

= 24 cm

The length of each side of the square will be :

Number of sides = 4

Length of each side :

24 / 4 = 6 cm

6 0
2 years ago
Vertical angles are congruent. Two nonadjacent angles formed by two intersecting lines are vertical angles.
Gnesinka [82]

Answer:

A

Step-by-step explanation:

If two nonadjacent angles formed by two intersecting lines = Vertical angles= congruent

Then

Two non adjacent angles formed by two intersecting lines are congruent

4 0
2 years ago
Read 2 more answers
which of the following is a result of shiftinga circle with equation (×-2)+(y-3)^2= 25 to the left 2 unit ?​
Paha777 [63]

Answer:

x^2+(y-1)^2=25

Step-by-step explanation:

eqn of circle : (x-h)^2+(y-k)^2=r^2

center of circle = (h,k)

hence, the center of the current circle is (2,3)

moving 2 units to the left would make the center (0,1)

the radius would remain the same (5) , hence the new eqn would be

(x-0)^2+(y-1)^2=25

x^2+(y-1)^2=25

4 0
2 years ago
What is the lowest and highest grade average in the class respectively?
sineoko [7]

\Huge\bf  \rightarrow \mid\mathcal{\underline{ \purple{Answer}}} \mid

<u> -76 and 95 is the lowest and highest grade average in the class, respectively.</u>

7 0
3 years ago
The times of the runners in a marathon are normally distributed, with a mean of 3 hours and 50 minutes and a standard deviation
balu736 [363]

Answer: 0.16

Step-by-step explanation:

Given that the run times provided are normally distributed ;

Mean(x) of distribution = 3 hours 50 minutes

Standard deviation(s) = 30 minutes

The probability that a randomly selected runner has a time less than or equal to 3 hours 20 minutes

3 hours 20 minutes = (3 hrs 50 mins - 30 mins):

This is equivalent to :

[mean(x) - 1 standard deviation]

z 1 standard deviation within the mean = 0.84

z, 1 standard deviation outside the mean equals:

P(1 - z value , 1standard deviation within the mean)

1 - 0.8413 = 0.1587

= 0.16

7 0
3 years ago
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