Answer:
(2,-8)*(-1,4)
a*b
the answer is (-2,-32)
(2)*(-1)=(-2)
(-8)*(4)=(-32)
Step-by-step explanation:
hope this helps you :)
Last week Gill read 164 of the 276 pages of the book.
hope this helped :)
Given in the problem is the diameter of the Ferris Wheel.
Thus, we can compute for the Ferris Wheel Circumference. This is the circular distance a single capsule attached to the wheel needs to do a full circle to.
Using 2 Step, we find the rate of how fast the capsule needs to be moving to complete 1 full cycle in 30 minutes.
1. Formula for computing the circumference
C = 2 x π x R
where R = Diameter divided by 2
C = 2π(120/2 )
C = 120π
2. Compute the rate or speed of the capsule / coach.
Rate or Speed = Distance to cover / Time it takes to cover
R/S = 120π/30 = 4π m/min or 12.57737 meters / min
5% of 1000 is 5 * 1000 / 100 = 5000 / 100 = 50.
Answer:
The center is -1,5 and the radius is 2
Step-by-step explanation:
Subtract 22 from both sides of the equation. x 2 + y 2 + 2 x − 10 y = − 22 Complete the square for x 2 + 2 x . ( x + 1 ) 2 − 1 Substitute ( x + 1 ) 2 − 1 for x 2 + 2 x in the equation x 2 + y 2 + 2 x − 10 y = − 22 . ( x + 1 ) 2 − 1 + y 2 − 10 y = − 22 Move − 1 to the right side of the equation by adding 1 to both sides. ( x + 1 ) 2 + y 2 − 10 y = − 22 + 1 Complete the square for y 2 − 10 y . ( y − 5 ) 2 − 25 Substitute ( y − 5 ) 2 − 25 for y 2 − 10 y in the equation x 2 + y 2 + 2 x − 10 y = − 22 . ( x + 1 ) 2 + ( y − 5 ) 2 − 25 = − 22 + 1 Move − 25 to the right side of the equation by adding 25 to both sides. ( x + 1 ) 2 + ( y − 5 ) 2 = − 22 + 1 + 25 Simplify − 22 + 1 + 25 . ( x + 1 ) 2 + ( y − 5 ) 2 = 4 This is the form of a circle. Use this form to determine the center and radius of the circle. ( x − h ) 2 + ( y − k ) 2 = r 2 Match the values in this circle to those of the standard form. The variable r represents the radius of the circle, h represents the x-offset from the origin, and k represents the y-offset from origin. r = 2 h = − 1 k = 5 The center of the circle is found at ( h , k ) . Center: ( − 1 , 5 ) These values represent the important values for graphing and analyzing a circle.
